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gregori [183]
3 years ago
9

If you divide one of the roots of the equation 4x2+bx−27=0 by the other root, the quotient will be −3. Find b.

Mathematics
1 answer:
klio [65]3 years ago
4 0
<h3>Answer:</h3>

  ±12   (two answers)

<h3>Explanation:</h3>

Suppose one root is <em>a</em>. Then the other root will be -3<em>a</em>. The product of the two roots is the ratio of the constant coefficient to the leading coefficient:

  (<em>a</em>)(-3<em>a</em>) = -27/4

  <em>a</em>² = -27/(4·(-3)) = 9/4

  <em>a</em> = ±√(9/4) = ±3/2

Then the other root is

  -3<em>a</em> = -3(±3/2) = ±9/2 . . . . . . the roots will have opposite signs

We know the opposite of the sum of these roots will be the ratio of the linear term coefficient to the leading coefficient: b/4, so ...

  -(a + (-3a)) = b/4

  2a = b/4

  b = 8a = 8·(±3/2)

  b = ±12

_____

<em>Check</em>

For b = 12, the equation factors as ...

  4x² +12x -27 = (2x -3)(2x +9) = 0

  It has roots -9/2 and +3/2, the ratio of which is -3.

For b = -12, the equation factors as ...

  4x² -12x -27 = (2x +3)(2x -9) = 0

  It has roots 9/2 and -3/2, the ratio of which is -3.

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Answer:

(9/2, 7/2)

Step-by-step explanation:

The easiest way to remember how to do this problem is to average the x-coordinates and average the y-coordinates.

So, in your problem (-3 + 12)/2 = 9/2   and  (-5 + 12)/2 = 7/2

The midpoint is (9/2, 7/2)

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8358.7

Step-by-step explanation:

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kkurt [141]
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Subtract 32 from both sides first, then divide both sides by 9/5
5 0
3 years ago
Determine whether a figure with the given vertices is a rectangle using the Distance Formula.
Alex Ar [27]

Answer:

Yes; Opposite sides are congruent, and diagonals are congruent.

Step-by-step explanation:

we have

A(4, -7), B(4, -2), C(0, -2), D(0, -7)

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the length of the sides

<u><em>Find the distance AB</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(4-4)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

AB=5\ units

<u><em>Find the distance BC</em></u>

substitute the values

d=\sqrt{(-2+2)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

BC=4\ units

<u><em>Find the distance CD</em></u>

substitute the values

d=\sqrt{(-7+2)^{2}+(0-0)^{2}}

d=\sqrt{(-5)^{2}+(0)^{2}}

CD=5\ units

<u><em>Find the distance AD</em></u>

substitute the values

d=\sqrt{(-7+7)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

AD=4\ units

Compare the length sides

AB=CD

BC=AD

therefore

Opposite sides are congruent

step 2

Find the length of the diagonals

<u><em>Find the distance AC</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(0-4)^{2}}

d=\sqrt{(5)^{2}+(-4)^{2}}

AC=\sqrt{41}\ units

<u><em>Find the distance BD</em></u>

substitute the values

d=\sqrt{(-7+2)^{2}+(0-4)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

BD=\sqrt{41}\ units

Compare the length of the diagonals

AC=BD

therefore

Diagonals are congruent

The figure is a rectangle, because Opposite sides are congruent, and diagonals are congruent

8 0
4 years ago
Read 2 more answers
In a basketball skills competition, Corson successfully made 5 of 7 shots and Charleigh made 3 of 5
xxTIMURxx [149]

Answer:

Corson had a better performance at the skills competition.

Step-by-step explanation:

In order to determine which player had a better performance at the skills competition, we need to find the percentage performance of both the players.

Therefore,

Corson's percentage performance

=\frac{5}{7}\times 100= 71.43%

Charleigh's percentage performance

=\frac{3}{5}\times 100= 60%

\because Corson's percentage performance > Charleigh's percentage performance

So, Corson had a better performance at the skills competition.

6 0
3 years ago
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