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4 years ago

Which of the following describes a situation where competition between producers exists

Chemistry

1 answer:

Oksanka [162]4 years ago

7 0

Answer:

C. two or more producers are trying to sell the same good or service to the same consumers.

Explanation:

APEX

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You need to produce a buffer solution that has a pH of 5.26. You already have a solution that contains 10. mmol (millimoles) of

Andreas93 [3]

The question is incomplete, complete question is :

You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.

Answer:

33.11 millimoles of acetate we will need to add to this solution.

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

Where :

tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid

[salt] = Concentration of salt

[Acid] = Concentration of salt

We have:

pH = 5.26

$pK_a=4.74$

[salt] = $[CH_3COO^-]$ = ?

[acid] = $[CH_3COOH]=10.0 mmol$

$5.26=4.74+\log(\frac{[CH_3COO^-]}{[10.0 mmol]})$

$[CH_3COO^-]=33.11 mmol$

33.11 millimoles of acetate we will need to add to this solution.

3 0

4 years ago

What volume (in liters, at 703 k and 2.04 atm) of chlorine gas is required to react with 3.39 g of p?

Natali5045456 [20]

The volume of chlorine required is 7.71 L.

The reaction between phosphorus and chlorine is:

2P + 5Cl₂→ 5PCl₅

Therefore, 2 moles of P requires 5 moles of chlorine to react with it.

Given mass of P =3.39 g

Molar mass of P=30.97 g/mol

No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles

2 moles of P requires 5 moles of chlorine

0.109 moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine

According to ideal gas equation

PV=nRT

2.04 x V = 0.2725 x 0.0821 x 703

V = 0.2725 x 0.0821 x 703 / 2.04

V = 7.71L

Learn more about ideal gas equation here:

brainly.com/question/3637553

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5 0

2 years ago

if atomic weight of nitrogen is 14.01 wshat is the mass of the notrogen atoms in one mole of cadium nitrate

lina2011 [118]

Cd(NO₃)₂ - cadmium nitrate

n{Cd(NO₃)₂}=1 mol ⇒ n(N)=2*1= 2 mol

m(N)=n(N)*A(N)

m(N)=2*14.01=28.02 g

5 0

4 years ago

A boy with pneumonia has lungs with a volume of 1.9 L that fill with 0.080 mol of air when he inhales. When he exhales, his lung

mariarad [96]

<u>Answer:</u> The number of moles of gas remaining in the lungs is 0.063 moles

<u>Explanation:</u>

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

where,

$V_1\text{ and }n_1$ are the initial volume and number of moles

$V_2\text{ and }n_2$ are the final volume and number of moles

We are given:

$V-1=1.9L\\n_1=0.080mol\\V_2=1.5L\\n_2=?$

Putting values in above equation, we get:

$\frac{1.9}{0.080}=\frac{1.5}{n_2}\\\\n_2=\frac{1.5\times 0.080}{1.9}=0.063$

Hence, the number of moles of gas remaining in the lungs is 0.063 moles

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Chuge%20%5Ctext%7Bwhat%20%5C%3A%20is%20%5C%3A%20acid%3F%3F%7D" id="TexFormula1" title=" \

maksim [4K]

An acid is a molecule or ion capable of either donating a proton, known as a acid, or, capable of forming a covalent bond with an electron pair, The first category of acids are the proton donors.

4 0

3 years ago