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5y - 3 = 3y + 27
2y = 30
y = 15
m<A= 5(15) - 3 = 75 - 3 = 72
m<B = [360 - 2(72)]/2
m<B = [360 - 144] / 2
m<B = 216 / 2
m<B = 108
Answer:
Tires that wear out by approximately 24307.8 miles will be replaces free of charge.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 27,000 miles
Standard Deviation, σ = 2100 miles
We are given that the distribution of life expectancy is a bell shaped distribution that is a normal distribution.
Formula:

We have to find the value of x such that the probability is 0.10
Calculation the value from standard normal z table, we have,
Tires that wear out by approximately 24307.8 miles will be replaces free of charge.
Answer:
all work is shown and pictured