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Stolb23 [73]
3 years ago
8

E.) MO(NO2)3 What’s the name

Chemistry
1 answer:
astraxan [27]3 years ago
4 0

Answer:

Molybdenum Nitrite

Explanation:

Mo => Molybdenum

NO2 => Nitrite

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How many moles of O2 are needed to react with 2.35 mol of C2H2?
Mrrafil [7]
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

2.35 mol C2H2 - x mol O2
2 mol C2H2 - 5 mol O2

x =  \frac{2.35 \times 5}{2}  = 5.875 \: mol
answer: 5.875 mol
5 0
3 years ago
Read 2 more answers
7.02 x 10^23 molecules of X2, a ssubstance consisting of diatomic molecules, has a mass of 296 grams. Determine the atomic weigh
Fiesta28 [93]

Answer:

d. 127 g/mol.

Explanation:

Hello!

In this case, since we have the amount of molecules of this this compound, we are able to compute the moles out there by using the Avogadro's number:

mol=7.02x10^{23}molec*\frac{1mol}{6.022x10^{23}molec}=1.17mol

Which correspond to the moles of X2. Then, by using the mass we are able to compute the molar mass of X2:

MM=\frac{296g}{1.17mol}\\\\MM=254g/mol

It means that the atomic mass of X halves the molar mass of X2, which is then d. 127 g/mol.

Best regards!

4 0
3 years ago
Chemistry: Molarity and Concentrations
kotegsom [21]
I dont know if this correct, but i hope it help

5 0
2 years ago
What is physical property?
ExtremeBDS [4]
A physical property is any property that is measurable, whose value describes a state of a physical system. The changes in the physical properties of a system can be used to describe its changes between momentary states. Physical properties are often referred to as observables. They are not modal properties. 
3 0
3 years ago
An analysis of a sugar compound is found to contain 132 grams of carbon (C), 22 grams of hydrogen (H), and 176 grams of oxygen (
ddd [48]
132 g of C  ,   22 g of H   , 176 g of O

132 + 22 + 176 => 330 g <span>of the substance

</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u        H = 1.0 u       O = 16.0 u

C = 132 / 12.0 => 11 moles

H = 22 / 1.0 => 22 moles

O = 176 / 16.0 => 11 moles

Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1

H = 22 / 11 => 2

O = 11 / 11 => 1

 formula empirically <span>is : CH</span>₂O

hope this helps!


8 0
3 years ago
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