Answer : The mass of helium gas in the balloon is, 1.23 grams.
Explanation : Given,
Volume of helium gas = 6.9 L
First we have to calculate moles of helium gas at STP.
As we know that, 1 mole of substance occupy 22.4 L volume of gas.
As, 22.4 L volume of helium gas present in 1 mole of helium
So, 6.9 L volume of helium gas present in
of helium
Now we have to calculate the mass of helium gas.

Molar mass of He gas = 4 g/mol

Thus, the mass of helium gas in the balloon is, 1.23 grams.
PbCl2 and PbCl4
Empirical formula is when the molecular formula is reduced (each element) by the same number until you are unable to do so any further.
CH2O cannot be further reduced, but C3H6O3 can all be divided by 3 making it CH2O (same empirical formula)
There are two main types of physical weathering: Freeze-thaw occurs when water continually seeps into cracks, freezes and expands, eventually breaking the rock apart. Exfoliation occurs as cracks develop parallel to the land surface a consequence of the reduction in pressure during uplift and erosion.
Answer:
Aluminum atoms are in 3.78 g of aluminum
02214076x10^23)8.4367659370640769254888x10^22 atoms, therefore there are 8.4367659370640769254888x10^22 atoms of Aluminum(Al) present in 3.78 grams of Aluminum(Al).
Explanation:
Answer:
1x10⁻¹²
Explanation:
- Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq)
At equilibrium:
The equilibrium constant for the the reaction can be written as:
[Cu⁺] is squared because it has a stoichiometric coefficient of 2 in the reaction. <em>Cu₂S has no effect on the constant because it is a solid</em>.
Now we can <u>calculate the equilibrium constant</u>:
- Keq = (1.0x10⁻⁵)² * 1.0x10⁻² = 1x10⁻¹²