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sattari [20]
3 years ago
9

When comparing differences in an amino acid residue at one position between the different proteins in the multiple alignment, wh

at factors do you think would be used to determine if a difference in an amino acid is a conserved change?
Chemistry
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

To understand the utility in sequence comparison and in the search for proteins that have a common evolutionary origin, you need to be clear about some concepts about how to evolve proteins. The idea that is accepted is that throughout the evolution some species are giving rise to new ones. Behind this is the genetic variation of organisms, that is, the evolution of genomes and their genes, as well as the proteins encoded by them.

Explanation:

Three ways can be distinguished by which genes evolve, and by proteins: mutation, duplication and shuffling of domains. When differences between homologous protein sequences are observed, these differences change to do with the way of life of the organism, an example of this, bacteria that live in hot springs at very high temperatures have proteins with a very high denaturation temperature, and these proteins are usually richer in cysteines. On the other hand, the fact that in positions of the sequences they remain unchanged (preserved positions), means that these have a special importance for the maintenance of the structure or function of the protein and its modification has not been tolerated throughout of evolution

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How many total moles of ions are released when the following sample dissolves completely in water? 6.188 x 10 21 formula units o
elixir [45]

Answer:

e. 3.08 x 10⁻² mol of ions.

Explanation:

  • Every 1.0 mole of any compound contains Avogadro's number of molecules (6.022 x 10²³).

  • We can get the no. of moles of NiCl₂ using cross multiplication:

1.0 mol NiCl₂ contains → 6.022 x 10²³ molecules.

??? mol NiCl₂ contains → 6.188 x 10²¹ molecules.

∴ The no. of moles of NiCl₂ = (1.0 mol)(6.188 x 10²¹ molecules)/(6.022 x 10²³ molecules) = 1.028 x 10⁻² mol.

  • NiCl₂ is ionized according to the equation:

NiCl₂ → Ni²⁺ + 2Cl⁻.

Which means that every 1.0 mol of NiCl₂ is ionized to produce 3.0 moles (1.0 mol of Ni²⁺ and 2 moles of Cl⁻).

<em>∴ The total moles of ions are released</em> = 3 x 1.028 x 10⁻² mol = <em>3.083 x 10⁻² mol of ions.</em>

3 0
3 years ago
A student titrates a 10.00mL sample of an HCl solution, using 0.359 M solution of NaOH. She finds that 24.75mL of sodium hydroxi
salantis [7]
HCl and NaOH react in a 1:1 ratio, meaning that 1 H+ from HCl will react with 1 OH- from NaOH. Knowing this, and that molarity is mol/liter, all we need to do is use what we have available. First we must find the mols of HCl in our solution, so we set up the following equation in the following steps:
1. 24.75mL x (0.359mol NaOH / 1000mL) = 8.885 x 10^-3mol NaOH
   This is done in order to find the mols of NaOH to convert to mols of HCl.
2. 8.885x10^-3mol NaOH x (1 mol HCl/1mol NaOH) = 8.885 x 10^-3mol HCl
   Here we just used the mols of NaOH we found to convert to mols of HCl using the 1:1 ratio described earlier.

From the mols of HCl all we have to do is divide by the amount of liters in the solution. Since we started with 10mL HCl and added 24.75mL NaOH, the total volume is 34.75mL = 0.03475L. So:
8.885 x 10^-3mol HCl/0.03475L = 2.557 x 10^-1M HCl
However, this is the molarity of the HCl and NaOH solution, not the original HCl solution. Using the dilution equation M1V1=M2V2, we can solve for the original molarity.
M1 = the molarity of our HCl in the titrated mixture (2.557 x 10^-1M HCl)
V1 = the total volume that our mixture has (34.75mL = 0.03475L)
M2 = what we're trying to find
V2 = the amount of the original HCl that we had (10mL = 0.010L)
Simply solving for M2 gives us:
M2 = (M1V1) / V2 or:
M2=((2.557 x 10^-1) x 0.03475L) / 0.010L = 8.89 x 10^-1M HCl. That is your answer.
6 0
3 years ago
A student walks 2 km in 30 minutes. What is the student’s average speed in km/h?
solmaris [256]
4 Km/Hr so.... 2/30=4/60
3 0
3 years ago
What forms of energy are involved when snow on a mountain breaks loose, resulting in an avalanche?
vitfil [10]
<span>During an avalanche, potential energy of the snow on the mountain is converted to kinetic energy as the snow cascades down. The conversion of potential energy to kinetic energy is due to the compacted atoms in the snow which will accumulate other snow resulting to a bigger snow that causes avalanche.</span>
4 0
4 years ago
More active metals will cause the reduction of less active metals. Less active metals will cause no reaction (N.R.) in more acti
beks73 [17]

Activity of metals with most active and less active metals are given below.

Explanation:

1. Activity of metals -Divide metals Based on the activity.

2. The primary difference between metals is the ability with which they undergo chemical reactions. The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive. Lithium, sodium, and potassium all react with water, for example. The rate of this reaction increases as we go down this column, however, because these elements become more active as they become more metallic.

3. Common Metals Divided into Classes on the Basis of Their Activity

  • Class I Metals: The Active Metals -Li, Na, K, Rb, Cs (Group IA)  ,Ca, Sr, Ba (Group IIA)
  • Class II Metals: The Less Active Metals -Mg, Al, Zn, Mn
  • Class III Metals: The Structural Metals -Cr, Fe, Sn, Pb, Cu
  • Class IV Metals: The Coinage Metals -Ag, Au, Pt, Hg

4. The most active metals are so reactive that they readily combine with the O2 and H2O vapor in the atmosphere and are therefore stored under an inert liquid, such as mineral oil. These metals are found exclusively in Groups IA and IIA of the periodic table.

5. Metals in the second class are slightly less active. They don't react with water at room temperature, but they react rapidly with acids.

6.The third class contains metals such as chromium, iron, tin, and lead, which react only with strong acids. It also contains even less active metals such as copper, which only dissolves when treated with acids that can oxidize the metal.

7. Metals in the fourth class are so unreactive they are essentially inert at room temperature. These metals are ideal for making jewelry or coins because they do not react with the vast majority of the substances with which they come into daily contact. As a result, they are often called the "coinage metals."

Fe⁺² (aq)+Zn(s)=>Zn⁺² (aq)+Fe(s)

3 0
3 years ago
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