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olga55 [171]
3 years ago
5

Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. what percentage of light was actually absorb

ed by the sample?
Mathematics
1 answer:
borishaifa [10]3 years ago
5 0

Using a spectrometer, a sample was analyzed to have a percent transmittance of 85%. This means that the remainder of the light was absorbed by the sample given in the question.

Now, from the 100% light that has been incident on the sample, if 85% was transmitted, then the percentage of light was actually absorbed by the sample can be found out as:

percentage of light was actually absorbed by the sample=100% - (percentage of light transmitted by the sample)

Therefore, percentage of light was actually absorbed by the sample=100%-85%=15%

Thus, 15% light was actually absorbed by the sample.

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3 years ago
What is 150% of 30? please answer lol
sdas [7]

Answer:

45

Step-by-step explanation:

When × by values higher than 100%, you divide the number by ten and add it to the number you are taking percentage of In this case, 15+30 = 45

4 0
2 years ago
Read 2 more answers
Hope someone can help me with this
postnew [5]

The perimeter:

40+35+16+16+125.7= 232.7 m

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3 years ago
Which graph representative this function
nalin [4]

Answer:

in graph A the vertex is (0,0)

in graph B the vertex is (0,3)

in graph C the vertex is (0,-3)

And in graph D the vertex is (0,-1)

The axis of symmetry for all of the is 0

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8 0
3 years ago
What is the approximate distance between points A and B?
Aleks04 [339]

Answer:

\displaystyle d \approx 7.62

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point A(1, 4)

Point B(-2, -3)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance<em> d</em>

  1. Substitute in points [DF]:                    \displaystyle d = \sqrt{(-2-1)^2+(-3-4)^2}
  2. (Parenthesis) Subtract:                       \displaystyle d = \sqrt{(-3)^2+(-7)^2}
  3. [√Radical] Exponents:                        \displaystyle d = \sqrt{9+49}
  4. [√Radical] Add:                                   \displaystyle d = \sqrt{58}
  5. [√Radical] Evaluate:                           d = 7.61577
  6. Round:                                                 \displaystyle d \approx 7.62
3 0
3 years ago
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