Answer:
Answer: 632 m.
Explanation:
We can divide the problem (and hence the total displacement over the runway) in two parts:
- Constant Negative Acceleration Time
- Constant Positive Acceleration Time.
1) The information that we have, is the initial velocity, the acceleration value, and the final value for the velocity during this part.
So, applying acceleration definition, we can find the time used in order to travel this part, as follows:
a = (vf - v₀) / t ⇒ t = (vf-v₀) / a = (25 m/s -100 m/s) / -15 m/s² = 5 s
Now, we can replace this value in the kinematic equation for displacement:
x = v₀ . t + 1/2 a t²
Replacing by the values, we get:
x= 100 m/s. 5s + 1/2 (-15 m/s²). (5²) s² = 500 m - 188 m = 312 m.
2) For this part, we have the values of acceleration, and of the final and initial velocity values, so we can find again the time for this part:
t = 3.43 s
Replacing in the equation for displacement, we have the distance traveled in this second part:
x = 25 m/s. (3.43s) + 1/2 (40 m/s²). (3.43)² s² = 320 m.
Explanation:
