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belka [17]
3 years ago
6

Which motion listed below matches the graph?

Physics
2 answers:
mote1985 [20]3 years ago
7 0
Bro I really think it might be c
N76 [4]3 years ago
5 0
Chouce-C is the motion described by the graph.
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Biologists use optical tweezers to manipulate micron-sized objects using a beam of light. In this technique, a laser beam is foc
sleet_krkn [62]

Answer:

a)   I = 1,894 10¹⁰ W / m², b)  E = 1.376 10⁵ N / C

Explanation:

a) intensity is defined as energy per unit area per unit time

          I = P / A

let's reduce the magnitudes to the SI system

         P = 10 mW = 10 10⁻³ W

         d = 0.82 μm = 0.82 10⁻⁶ m

the laser area is

         A =π r² = π d²/4

         A =π (0.82 10⁻⁶)²/4

         A = 5.28 10⁻¹³ m²

we calculate

          I = \frac{10 \ 10^{-3}}{5.28 \ 10^{-13}}

          I = 1,894 10¹⁰ W / m²

b) average intensity and electric field are related

          I = E * E

          E = √I

          E = \sqrt{1.894 \ 10^{10}}

          E = 1.376 10⁵ N / C

4 0
3 years ago
Write any two importance of gravitational force​
saul85 [17]

Answer:

plz mark me as brainliest plz

Explanation:

The gravitational force of the earth keeps us bound to the earth. Gravitational force between earth and sun makes the earth move around the sun. Gravitational force between moon and earth makes the moon go around the earth.

5 0
3 years ago
Compare and contrast light waves and sound waves
Naddika [18.5K]
The difference between light waves and sound waves are that sound waves travel faster than light wave and have a frequency range while light waves have a to me range.
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3 years ago
While performing an experiment involving a reaction between two chemicals, the scientist observes that the reaction container ha
AVprozaik [17]
When an object is becomes warm its an example of exothermic reaction.
8 0
3 years ago
Two wheels with fixed hubs, each having a mass of 1kg , start from rest, and forces are applied: F1= 1 N to the first wheel and
irina [24]

Answer:

2N

Explanation:

m = m_1 = m_2 = 1 kg

The torques generated by tangential forces on the 2 wheels are

T_1 = F_1R_1 = 1*0.5 = 0.5 Nm

T_2 = F_2R_2 = F_2*1 = F_2 Nm

According to Newton's 2nd law, the angular accelerations generated by these torque would be

\alpha_1 = \frac{T_1}{I_1} = \frac{0.5}{mR_1^2} = \frac{0.5}{1*0.5^2} = 2 rad/s^2

\alpha_2 = \frac{T_2}{I_2} = \frac{F_2}{mR_2^2} = \frac{F_2}{1*1^2} = F_2 rad/s^2

For the 2nd wheel to have the same angular acceleration, its force must be

\alpha_1 = \alpha_2

2 = F_2

F_2 = 2N

6 0
3 years ago
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