kinematics allows to find the kinetic variables and the relationships between position, speed and acceleration, for launching projectiles we can find:
a) The horizontal velocity vₓ = 2.1 m/s
b) The height of the table y₀= 0.60 m
given parameters
- Time to reach the floor t = 0.35 s
- Horizontal distance x = 0.75 m
to find
a. Horizontal speed
b. table height
Let's use the kinematics relations, let's start by defining a reference frame with the x-axis along the motion of the ball and the vertical y-axis with the positive direction up.
We look for the initial velocity in the x axis, there is no acceleration we can use the uniform kinematic relations
vₓ = x / t
Where vx is the horizontal velocity, g the acceleration of gravity (g=9.8 m/s²) and t the time
vₓ = 0.75 / 0.35
vₓ = 2.14 m / s
We look for the height of the table that corresponds to the initial height (y₀) of the ball, when reaching the floor the height is zero, on the vertical axis the initial velocity is zero (v_{oy} = 0)
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
y₀ = ½ 9.8 0.35²
y₀i = 0.60 m
- In conclusion with the kinematic relations for the launch of projectiles we can find the horizontal velocity vₓ = 2.1 m / s and the height of the table i = 0.60 m
learn more about projectile launch here:
brainly.com/question/12792922
Answer:
Each jump covers one center of the square to the other. If you can imagine the scenario, a single jump would cover a length of the side of one whole square. So, if it took three jumps, the total distance would be
d = 3 * 5 cm
d = 15 cm
Therefore, the magnitude or distance is 15 cm. The displacement depends on the direction of motion.
Answer:
Speed of the soccer ball with respect to ground is ZERO
Explanation:
As we know that truck is moving with speed 20 mph
Now a soccer ball is shoot from truck with respect to the motion of truck in opposite direction
The relative speed of the soccer ball is
now we know that
so we have
so we have
Answer:
I'm pretty sure it's air pressure.
Explanation:
