V=(1/3)hpir^2
v=130
h=13
r=x
130=(1/3)(13)pix^2
times both sides by 3
390=13pix^2
divide both sides by 13
30=pix^2
divide both sides by pi
30/pi=x^2
sqrt both sides
x≈3.09
radius is abou 3 units
Answer:
1) x = 42 ; y = 42
2) x = 72 ; y = 48 ; z = 60
Step-by-step explanation:
1)
x + 42 + 96 = 180
x + 138 = 180
x = 42
y + 42 + 96 = 180
y + 138 = 180
y = 42
2)
x + 108 = 180
x = 72
y + 132 = 180
y = 48
z + x + y = 180
z + 72 + 48 = 180
z + 120 = 180
z = 60
Answer:
49N
Step-by-step explanation:
Step one
Given
When the force of 63 N acts on a certain object
the acceleration of the object is 9/ms^2
Firstly, we need to calculate the mass m
F=ma-------1
m= F/a
m= 63/9
m= 7kg
Step two:
Also, if the acceleration of the object becomes 7 m/s^2
then the force
Note: the mass remains the same= 7kg
F=ma
F=7*7
F= 49N
The statement is always true because right angles measure 90 degrees and if you add them you get 180 and supplementary angles are angles that add up to 180.
Hope this helps :)
