17. Is sodium hydroxide (NaOH) an acid or base?

Over long time scales the solubility-temperature feedback (below), can affect climate. An increase in atmospheric CO2 concentrat

Mars2501 [29]

The fact that CO2 is released from oceans due to further rise in temperature is an example of a negative feedback.

A negative feedback is one in which the process that produces the feedback is interrupted. That is, the process is stopped as a result of the feedback received.

In this case, CO2 which leads to global warming dissolves in the ocean which serves a large sink for the gas. However, as the increase in ocean temperatures causes decrease in solubility of CO2, more CO2 is released leading to further temperature rise. This is an example of a negative feedback loop.

Learn more: brainly.com/question/13440572

5 0

3 years ago

Find Number of protons, neutrons and electrons in next atoms:

Dennis_Churaev [7]

Answer:

hi nice person. i need brain points sorry it not answer the question.

Explanation:

7 0

3 years ago

A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure.

daser333 [38]

Answer:

1.429 g of N₂

Explanation:

The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:

N₂ ₍g₎ + 3 H₂ ₍g₎ ⇆ 2NH₃ ₍g₎

One can note that 1 mol of N₂ react with H₂ to produce 2 mol of NH₃.

We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.

no. of moles of NH₃ = (mass / molar mass) = (1.7 g / 17 g/mol) = 0.1 mol

and the actual yield is 98% , then the theoretical number of moles that would be produced are:

percent yield = (actual yield / theoretical yield) × 100

98 = (0.1 mol / theoretical yield) × 100

theoretical no. of moles of NH₃ = (0.1 * 100) /98 = 0.102 mol

using cross multiplication

1 mol of N₂ → 2 mol of NH₃.

?? mol of N₂ → 0.102 mol of NH₃.

no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol

Last step is to convert the moles back to grams using:

mass = (no of moles of N₂ * molar mass of N₂)

= (0.051 mol * 28 g/mol) = 1.429 g

5 0

4 years ago

Compare how entropy changes for the following two systems:

DanielleElmas [232]

Answer:

Explanation:

Entropy is concept which the describes the state of randomness or disorderliness of particles of a system. The entropic level depends on two important factors:

1. Temperature

2. Physical state of matter

For system A, in going from solid to liquid by dissolution in water the entropy increases. Solids are the most ordered substances followed by liquids. Gases are the most random.

For system B, moving from gas to a condensed state, there is a huge decrease in randomness of the system. The system tends towards more orderliness as the condensing forces changes a gas to a liquid. For this system, entropy reduces.

5 0

4 years ago

Read 2 more answers

Many computer chips are manufactured from silicon, which occurs in nature as SiO2 . When SiO2 is heated to melting, it reacts wi

Ierofanga [76]

Answer:

a. Theoretical yield of Si = 72.58 kg

b. Percent Yield = 91.2 %

Explanation:

The chemical reaction involved is: SiO₂ (l) + 2C (s) → Si (l) + 2CO (g)

The stoichiometric ratio = 1 mol SiO₂ ÷ 2 mol C = 0.5 mol SiO₂ ÷ 1 mol C

Given: mass of SiO₂: w₁ = 155.3kg = 155.3 × 10³g, mass of C: w₂ = 79.3kg = 79.3 × 10³g, mass of Si: w₃ = 66.2kg = 66.2 × 10³g (∵ 1 kg =1000g)

Molar mass of SiO₂: m₁ = 60.08 g/mol, atomic mass of C: m₂ = 12.01 g/mol, atomic mass of Si: m₃ = 28.08 g/mol

Number of moles of SiO₂ taken: n₁ = w₁ ÷ m₁ = 155300 g ÷ 60.08 g/mol = 2584.88 mol

Number of moles of C taken: n₂ = w₂ ÷ m₂ = 79300 g ÷ 12.01 g/mol = 6602.83 mol

Actual ratio = n₁ ÷ n₂ = 2584.88 mol SiO₂ ÷ 6602.83 mol C = 0.39 mol SiO₂ ÷ 1 mol C

Since the stoichiometric ratio > actual ratio

Therefore, SiO₂ is the limiting reagent.

Now, the mass of SiO₂ in 1 mol = number of moles × molar mass = 1 mol × 60.08 g/mol = 60.08 g

the mass of Si in 1 mol = number of moles × molar mass = 1 mol × 28.08 g/mol = 28.08 g

So 28.08 g of Si is produced from 60.08 g SiO₂

Therefore, the amount of Si produced from 155300 g SiO₂ = 155300 g × 28.08 g ÷ 60.08 g = 72583.62 g = 72.58 kg

Therefore, the theoretical yield of Si = 72.58 kg

Actual yield of Si = 66.2 kg

Therefore, Percent Yield = Actual yield ÷ Theoretical yield × 100 = 66.2 kg ÷ 72.58 kg × 100 = 91.2 %

3 0

3 years ago