Answer:
4.76
Explanation:
In this case, we have to start with the <u>buffer system</u>:
We have an acid () and a base (). Therefore we can write the <u>henderson-hasselbach reaction</u>:
If we want to calculate the pH, we have to <u>calculate the pKa</u>:
According to the problem, we have the <u>same concentration</u> for the acid and the base 0.1M. Therefore:
If we divide:
If we do the Log of 1:
So:
With this in mind, the pH is 4.76.
I hope it helps!
Answer:
C.) 1345.5 J
Explanation:
To find the energy, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy (J)
-----> m = mass (g)
-----> c = specific heat (J/g°C)
-----> ΔT = change in temperature (°C)
The specific heat of aluminum is 0.89 J/g°C. You can plug the given values into the equation and solve.
Q = mcΔT
Q = (150 g)(0.89 J/g°C)(10 °C)
Q = 1335
*It is up to you whether you wish to trust this answer. My answer may be slightly different due to using a different specific heat.
The mass is 4.4435, I think hope this helps