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alexandr1967 [171]
3 years ago
15

How many moles of MgS2O3 are in 221 g of the compound?

Chemistry
1 answer:
maksim [4K]3 years ago
6 0
MgS2o3 weights (24.305) + 3(16) grams pre mole so if you divide 181 g by that number you will have the number of moles. Grams*(moles/grams)=moles
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CO
KonstantinChe [14]

Answer:

1) The number of the listed compounds that have ionic bonds between them are 5 compounds

2) Their formulas showing their charges within the compounds are;

NaCl ↔ Na⁺+Cl⁻

MgO ↔ Mg²⁺+O²⁻

K₂O ↔ 2K⁺+O²⁻

LiF ↔Li⁺+F⁻

CaO ↔ Ca⁺+O²⁻

3) The major reason they were selected is because they are compounds formed by the combination of a metal and a nonmetal

Explanation:

1) An ionic bond involves the transfer of an atoms valence to another atom, such that the ions formed by the ionic chemical bond will be oppositely charged

Therefore, metals, which are elements that mainly have a few electrons in their outermost shell, loses their valence electrons and become positively charged, while non metals, which require a few electrons to complete the stable octet electronic configuration, receive the electrons from the metallic atoms and become negatively charged

Therefore, the compounds formed between a metal and a nonmetal in the list are the the compounds containing ionic bonds, including

NaCl, MgO, K₂O, LiF, and CaO

Therefore, 5 compounds contain ionic bonds between them;

2) Their formulas are;

NaCl, MgO, K₂O, LiF, and CaO

3) The major reason that the chosen compounds contain ionic bonding between them is because they involve the combination of a metal and a nonmetal as follows;

a) NaCl → Na⁺ (metal ion) + Cl⁻(nonmetal ion)

b) MgO → Mg²⁺ (metal ion) + O²⁻(nonmetal ion)

c) K₂O → 2K⁺ (metal ion) + O²⁻(nonmetal ion)

d) LiF → Li⁺ (metal ion) + F⁻(nonmetal ion)

e) CaO → Ca⁺ (metal ion) + O²⁻(nonmetal ion)

6 0
3 years ago
Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 4.1 g of butane is m
m_a_m_a [10]

Answer:

12.44 g

Explanation:

2C4H10 + 13O2 = 8CO2 + 10H2O

n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).

n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).

Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.

mass of CO2 produced =

M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol

M = 0.5656/2 * 44

M = 0.2828 * 44

M = 12.44 of CO2

5 0
3 years ago
Please assist me with chemistry assessment
Lera25 [3.4K]

Answer:

I don't know

Explanation:

7 0
1 year ago
A)<br>Name the following compounds<br>CH, -CH-CH<br>(i)<br>CH, Br<br>-​
liq [111]

Answer:

methyl, ethyl,

Explanation:

that should be the case

8 0
3 years ago
The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa
Ostrovityanka [42]

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

6 0
3 years ago
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