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alexandr1967 [171]
3 years ago
15

How many moles of MgS2O3 are in 221 g of the compound?

Chemistry
1 answer:
maksim [4K]3 years ago
6 0
MgS2o3 weights (24.305) + 3(16) grams pre mole so if you divide 181 g by that number you will have the number of moles. Grams*(moles/grams)=moles
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4 0
3 years ago
The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

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The molarity can be determined by using the formula,

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= 0.027420/0.312

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6 0
2 years ago
the half of an oxidation-reduction reaction shows the iron gains. what does this electron gain mean for iron.
Nataly [62]

The correct answer is option C, that is, it is reduced.

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In the given case, iron gains electrons mean that it is reduced.  


3 0
3 years ago
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