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Pavel [41]
3 years ago
10

What volume (in mililiters) of oxygen gas is required to react with 4.03 g of my at stp

Chemistry
1 answer:
goldenfox [79]3 years ago
4 0

You must use 1880 mL of O₂ to react with 4.03 g Mg.

A_r: 24.305

         2Mg + O₂ ⟶ 2MgO

<em>Moles of Mg</em> = 4.03 g Mg × (1 mol Mg/24.305 g Mg) = 0.1658 mol Mg

<em>Moles of O₂</em> = 0.1658 mol Mg × (1 mol O₂/2 mol Mg) = 0.082 90 mol O₂

STP is 25 °C and 1 bar. At STP, 1 mol of an ideal gas has a volume of <em>22.71 L</em>.

<em>Volume of O₂</em> = 0.082 90 mol O₂ × (22.71 L O₂/1 mol O₂) = 1.88 L = 1880  mL

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How many moles of Au are in 312 g of Au?
Talja [164]

Answer:

1.583 moles

Explanation:

Rounded Atomic Mass of Au = 197 grams

\frac{312}{197} =1.5837, 1.584

7 0
3 years ago
I will give brainiest please help
gizmo_the_mogwai [7]

Answer: D and A

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4 0
3 years ago
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3 years ago
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A mass of 2.20 g carbon monoxide is reacted with 4.86 g hydrogen to form methanol.CO(g) + 2 H2(g) → CH3OH(g)The reaction is perf
iogann1982 [59]

Answer:

The partial pressure in mm Hg for each of the species are:

PCO = 0

PH2 = 3874

PCH3OH = 347

The total pressure is 4221

Explanation:

We have to use Ideal gas equation PV = nRT and Partial pressure rule Total Pressure= ∑ Partial pressures.

We have following data:

T= 357K (85+272); nCO=0.078 (2.2/28); nH2 = 2.43 (4.86/2); R=62.36

With equation CO(g) + 2 H2(g) → CH3OH(g) we can calculate the amount of moles the reaction has finished. The limit reagent is CO because is consumed completely and moles CO in flask are 0. According to equation, every CO mol produces one CH3OH mol. That means 0.078 CO moles produces 0.078 CH3OH moles. From Ideal gas equation we have P=nRT/V.

Applying:

PH2=0.87*62.36*357/5=3874

PCH3OH =0.078*62.36*357/5=347

Total P = 3874+347=4221

I hope my answer helps you

7 0
3 years ago
Consider the reaction below. Which species is(are) the Brønsted-Lowry acid(s)?
madreJ [45]

Answer:

HF is the acid

Explanation:

The Brønsted-Lowry theory defines the acids and bases in chemistry as follows:

An acid is the species that can donate a proton

A base can accept protons.

In the reaction:

HF(aq) + NH₃(aq) → NH₄⁺(aq) + F⁻(aq)

As you can see, HF can donate its proton to produce F⁻: HF is the acid

<em>In the same way, NH₃ is accepting a proton, NH₃ is the base.</em>

5 0
3 years ago
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