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Artist 52 [7]
3 years ago
6

A jury pool consists of 6 men and w women. If 2 jurors are selected from the pool at random, is the probability that 2 men will

be selected higher than the probability that 1 man and 1 woman will be selected?
Social Studies
1 answer:
telo118 [61]3 years ago
7 0

Answer:

Yes, it is higher if w ≥ 3.

Explanation:

Given,

Number of men = 6,

Number of women = w,

Ways of choosing 2 men = C(6,2),

There can be two cases,

Case 1 :

If w ≥ 3,

Then the number of ways of choosing 1 men and 1 women > Ways of choosing two men,

So, the probability of choosing 1 men and 1 women is greater than that of choosing two men,

For eg : If w = 8,

^8C_1\times ^6C_1>^6C_2

\implies \frac{^8C_1\times ^6C_1}{^{14}C_2}>\frac{^6C_2}{^{14}C_2}

Similarly if w = 3,

\implies \frac{^3C_1\times ^6C_1}{^{14}C_2}>\frac{^6C_2}{^{14}C_2}

Case 2 :

If 0 < w < 3,

Then the number of ways of choosing 1 men and 1 women < Ways of choosing two men,

So, the probability of choosing 1 men and 1 women is less than that of choosing two men

eg :

\frac{^2C_1\times ^6C_2}{^{14}C_2}

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