Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value = = 5.29
Answer:
8*8=64
Step-by-step explanation:
Don't worry! Keep on trying! I hope this helps! Have a great rest of your day!
Answer:
$9.36
Step-by-step explanation:
First 12.5 - 5.3 = 7.2
7.2 x 1.30 = 9.36
The domain in a relation y(x) is the set of values for which the relation is defined (the values on x, where y is defined)
In this relation the values wich the relation is defined is: the coordinates of x where there are a point:
Domain: -1, 0, 3
The range in a relation y(x) is the set of all the values that y(x) takes (the values of y)
In this relation the values that takes y(x) are the coordinates of y where there are a point:
Range: -3, -1, 0