Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
Answer:
889674568890
Step-by-step explanation:
I used a calculator :)
Answer:
x= 3 +
, 3 -
Step-by-step explanation:
You use the quadratic formula to get x= 
Then you simplify and get the answers x= 3 +, 3 -
She regrouped the numbers instead of multiplying like 8b(2b-r) -4r(2b-r).
