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2 years ago

8

What is the 4th term in the sequence b(n)=1(-2)^n-1

1 answer:

marishachu [46]2 years ago

7 0

Answer:

<h2>The answer is 8</h2>

Step-by-step explanation:

From the question the formula for the sequence is

$b(n) = 1 ({ - 2})^{n - 1}$

where

n is the nth term in the sequence

Since we are finding the 4th term n = 4

Substitute this value of n into the above formula

That's

$b(4) = 1 ({ - 2})^{4 - 1} \\ = 1 ({ - 2})^{3} \\ = { - 2}^{3}$

We have the final answer as

<h3>8</h3>

Hope this helps you

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Notice the picture below

$\bf \textit{equation of a circle}\\\\
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\qquad center\ ({{ h}},{{ k}})\qquad
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-----------------------------\\\\
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Step-by-step explanation:

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3 years ago

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2 years ago

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jeka57 [31]

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<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

The coin is fair, hence p = 0.5.

The coin is tossed 10 times, hence n = 10.

The probability that is lands tails up at least nine times is given by:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

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Hence:

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More can be learned about the binomial distribution at brainly.com/question/24863377

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2 years ago

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