Question

What is the 4th term in the sequence b(n)=1(-2)^n-1

Answer 1

Answer:

The answer is 8

Step-by-step explanation:

From the question the formula for the sequence is

$b(n) = 1 ({ - 2})^{n - 1}$

where

n is the nth term in the sequence

Since we are finding the 4th term n = 4

Substitute this value of n into the above formula

That's

$b(4) = 1 ({ - 2})^{4 - 1} \\ = 1 ({ - 2})^{3} \\ = { - 2}^{3}$

We have the final answer as

8

Hope this helps you