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3 years ago

What value should she use as the common ratio 0.05

Mathematics

1 answer:

pychu [463]3 years ago

4 0

Answer:0.50

Step-by-step explanation:

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Which of the following has a slope of negative 2 in the y-intercept of 4? A) y= -2x-4

Setler [38]

D
uses the the formula y=mx+b and m is the slope. b is the y intercept.

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4 years ago

Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

Therefore, the domain of this function is: -∞ < -1 or x > 0

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3 years ago

3/4 + ( 1/3 divided by 1/6 - (-1 /2 a. 3/4 b. 1 3/4 c. 3 1/4 d. 2 1/4

andrew-mc [135]

answer:

A is the answer because you need to divide it and add it together and then u get 3.25 which is also a fraction for 3/4

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4 years ago

The points scored by a basketball team in its last 6 games

Debora [2.8K]

Answer:

73+78+85+84+37+115 because you will add all point scored by the last 6games =471

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2 years ago

g A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 13

Luden [163]

Answer:

There is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43

Step-by-step explanation:

A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135°F.

So, Null hypothesis: $H_0:\mu \geq 135$

Alternate hypothesis : $H_a:\mu$

To test this claim, you randomly select a sample of 32 systems and find the mean activation temperature to be 133°F.

x=133

n = 32

Population Standard deviation = $\sigma = 3.3^{\circ}F$

Formula : $z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}\\\\z=-3.428$

z=-3.43

Refer the z table for p value

p value = 0.0003

$\alpha = 0.10$

p value < α

So, we failed to accept null hypothesis

Hence there is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43

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3 years ago