Answer:
bende sadece benim böyle diye düşünüyordum
Answer: W = 0.8 J
Explanation:
At 0.12 m the force is 3.0 N
At 0.28 m the force is 7.0 N
The distance of stretch is 0.28 - 0.12 = 0.16 m
The AVERAGE force is (3.0 + 7.0) / 2 = 5.0 N
The work is
W = Fd = 5.0(0.16) = 0.8 J
or
A formula guy might find the slope of the line
k = 7 N / 0.28 m = 25 N/m
PS = ½kx²
PS = ½(25)0.28² - ½(25)0.12² = 0.8 J
or
A charts gal might realize that the work is the area under the curve between the limits
W = A = (0.28 - 0.12)[3.0 + ½(7.0 - 3.0)] = 0.8 J
or
A math guy might find an equation for the line and integrate between the limits.
y = 25x
W = for b = 0.12 and a = 0.28
W = 12.5x² | for b = 0.12 and a = 0.28
W = 12.5(0.28)² - 12.5(0.12)²
W = 0.8 J
Answer:
t = 25.5 min
Explanation:
To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.
Next, you calculate the difference between both times t1 and t2:
This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:
hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph
<span>The
temperature at which the vapor pressure of a liquid equals the
environmental pressure surrounding the liquid is best defined as:
Boling Point
</span>
Answer:
55,42 J
Explanation:
Since the height of the room is 3.45 m (distance between the floor and the ceiling) the difference between this value and the length of the rope 1.19 m; it will be equal to (3.45-1.19) =2.26 m. If we take as a reference point (Ep=0) the floor of the room, then the potential energy will be equal to Ep = M * g * h, replacing values in this equation (2.5 kg * 9.81 m/s2 * 2.26 m) will be 55,42 (N * m) or Jules.