All categories

2 years ago

Help with 3 and check the other ones please :(

Physics

2 answers:

devlian [24]2 years ago

7 0

I don’t know what your talking about. ?!?!?!?

alekssr [168]2 years ago

7 0

Um there’s no pictures on here for me to help you with if you put a picture maybe I’ll be able to help you

You might be interested in

You drop an ice cube into an insulated flask full of water and wait for the ice cube to completely melt. The ice cube initially

3241004551 [841]

Answer: $T=12.69^{\circ}C$

Explanation:

Given

Mass of ice $m=60 gm$

mass of water $M=760 gm$

Initial Temperature of water $T_i=20^{\circ}C$

Let T be the Final Temperature of mixture

Latent heat of Fusion $L=334 J/gm$

heat required to melt ice completely is

$Q_1=60\times 334=20.04 kJ$

Heat released by water is taken by ice thus

$Mc_{water}(20-T)=mL+mc_{water}(T-0)$

$0.76\times 4.184\cdot (20-T)=20.04+0.06\times 4.184\cdot (T)$

$T=12.69^{\circ}C$

7 0

2 years ago

What are the types of energies released when a candle burns?

Phantasy [73]

When a candle is burning the candle is releasing thermal and radiant energy

4 0

3 years ago

Read 2 more answers

Which of the following does not lead to addiction?

zloy xaker [14]

Answer:

Obesity does not lead to addiction. Obesity is a weight condition characterized by a body.

Explanation:

5 0

2 years ago

The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it 0.90 s to reach the floor. Wha

Anna007 [38]

Answer:

The mass of the another block is 60 kg.

Explanation:

Given that,

Mass of block M= 100 kg

Height = 1.0 m

Time = 0.90 s

Let the mass of the other block is m.

We need to calculate the acceleration of each block

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$1.0=0+\dfrac{1}{2}\times a\times(0.90)^2$

$a=\dfrac{2\times1.0}{(0.90)^2}$

$a=2.46\ m/s^2$

We need to calculate the mass of the other block

Using newton's second law

The net force of the block M

$Ma=Mg-T$

$T=Mg-Ma$ ....(I)

The net force of the block m

$ma=T-mg$

Put the value of T from equation (I)

$ma=Mg-Ma-mg$

$m(a+g)=M(g-a)$

$m=\dfrac{M(g-a)}{(a+g)}$

Put the value into the formula

$m=\dfrac{100(9.8-2.46)}{2.46+9.8}$

$m=59.8\ \approx60\ kg$

Hence, The mass of the another block is 60 kg.

8 0

2 years ago

A 60-W, 120-V light bulb and a 200-W, 120-V light bulb are connected in series across a 240-V line. Assume that the resistance o

gulaghasi [49]

A. 0.77 A

Using the relationship:

$P=\frac{V^2}{R}$

where P is the power, V is the voltage, and R the resistance, we can find the resistance of each bulb.

For the first light bulb, P = 60 W and V = 120 V, so the resistance is

$R_1=\frac{V^2}{P}=\frac{(120 V)^2}{60 W}=240 \Omega$

For the second light bulb, P = 200 W and V = 120 V, so the resistance is

$R_1=\frac{V^2}{P}=\frac{(120 V)^2}{200 W}=72 \Omega$

The two light bulbs are connected in series, so their equivalent resistance is

$R=R_1 + R_2 = 240 \Omega + 72 \Omega =312 \Omega$

The two light bulbs are connected to a voltage of

V = 240 V

So we can find the current through the two bulbs by using Ohm's law:

$I=\frac{V}{R}=\frac{240 V}{312 \Omega}=0.77 A$

B. 142.3 W

The power dissipated in the first bulb is given by:

$P_1=I^2 R_1$

where

I = 0.77 A is the current

$R_1 = 240 \Omega$ is the resistance of the bulb

Substituting numbers, we get

$P_1 = (0.77 A)^2 (240 \Omega)=142.3 W$

C. 42.7 W

The power dissipated in the second bulb is given by:

$P_2=I^2 R_2$

where

I = 0.77 A is the current

$R_2 = 72 \Omega$ is the resistance of the bulb

Substituting numbers, we get

$P_2 = (0.77 A)^2 (72 \Omega)=42.7 W$

D. The 60-W bulb burns out very quickly

The power dissipated by the resistance of each light bulb is equal to:

$P=\frac{E}{t}$

where

E is the amount of energy dissipated

t is the time interval

From part B and C we see that the 60 W bulb dissipates more power (142.3 W) than the 200-W bulb (42.7 W). This means that the first bulb dissipates energy faster than the second bulb, so it also burns out faster.

7 0

2 years ago