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igor_vitrenko [27]
2 years ago
13

Help with 3 and check the other ones please :(

Physics
2 answers:
devlian [24]2 years ago
7 0
I don’t know what your talking about. ?!?!?!?
alekssr [168]2 years ago
7 0
Um there’s no pictures on here for me to help you with if you put a picture maybe I’ll be able to help you
You might be interested in
A cannon ball launched horizontally with a speed of 20m/s and a baseball dropped off a cliff and it accelerates at a rate of 10m
miskamm [114]
If they both start from the same height, then they both hit the ground at the
same time.  It makes no difference if their horizontal speeds aren't equal.
The cannon ball still accelerates downward at the same rate as the baseball.
8 0
3 years ago
How much conventional current must you run in a solenoid with radius = 0.05 m and length = 0.39 m to produce a magnetic field in
Ugo [173]

Answer:

Explanation:

radius of the solenoid, r = 0.05 m

length of the solenoid, l = 0.39 m

Magnetic field of the solenoid, B = 2 x 10^-5 T

Number of turns, N = 200

The magnetic field of the solenoid is given by

B=\mu _{0}ni

where, i be the current and n be the number of turns per unit length

n = N / l = 200 / 0.39 = 512.8

2\times 10^{-5}=4 \times 3.14\times 10^{-7}\times 512.8\times i

i = 0.031 A

3 0
3 years ago
A particle in uniform circular motion requires a net force acting in what direction?
mel-nik [20]
The net force will point towards the acceleration of the object, as supported by Newton's second law.
6 0
3 years ago
When you irradiate a metal with light of wavelength 433 nm in an investigation of the photoelectric effect, you discover that a
sergij07 [2.7K]

Answer:

The right solution is:

(a) 2.87 eV

(b) 1.4375 eV

Explanation:

Given:

Wavelength,

= 433 nm

Potential difference,

= 1.43 V

Now,

(a)

The energy of photon will be:

E = \frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}

  = 4.59\times 10^{-19} \ J

or,

  = \frac{4.59\times 10^{-19}}{1.6\times 10^{-19}}

  = 2.87 \ eV

(b)

As we know,

⇒ Vq=\frac{hc}{\lambda}-\Phi_0

By substituting the values, we get

⇒ 1.43\times 1.6\times 10^{19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}-\Phi_0

⇒                       \Phi_0=2.3\times 10^{-19} \ J

or,

⇒                            =\frac{2.3\times 10^{-19}}{1.6\times 10^{-19}}

⇒                            =1.4375 \ eV

5 0
3 years ago
With which of the following statements would Whorf and Sapir agree?
ASHA 777 [7]
Hi!

The answer is <span>B. Language influences how people understand their world.

Hope this helps!

-Payshence xoxo</span>
6 0
3 years ago
Read 2 more answers
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