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kozerog [31]
3 years ago
9

How do remote sensitive satellites help people stay safe from massive fires

Physics
1 answer:
rodikova [14]3 years ago
7 0
Satellites would be able to detect fires when they start and allow human monitors to review the information and issue warnings.
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John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x a
Anna11 [10]

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john m_1=95.6 kg

Mass of barbara m_2=55.3 kg

John is standing at x=10.9 m

Barbara is standing at x=2.50 m

x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}

x_{com}=\frac{95.6\times 10.9+55.3\times 2.5}{95.6+55.3}

x_{com}=\frac{1180.29}{150.9}

x_{com}=7.821 m

Now if they change their Position then

x'_{com}=\frac{95.6\times 2.5+55.3\times 10.9}{95.6+55.3}

x'_{com}=\frac{841.77}{150.9}

x'_{com}=5.578

Thus we can see that center of mass shifted towards left by a distance of 2.243 m because heavier is shifted towards left

8 0
3 years ago
A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uni
ad-work [718]

Answer:

The magnetic force on the section of wire is -2.925\hat{j}\ N.

Explanation:

Given that,

Current I = 2.60\hat{i}\ A

Length = 0.750 m

Magnetic field B = 1.50\hat{k}\ T

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

\vec{F}=l\vec{I}\times\vec{B}

\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}

Since, \hat{i}\times\hat{k}=-\hat{j}

\vec{F}=-2.925\hat{j}\ N

Hence, The magnetic force on the section of wire is -2.925\hat{j}\ N.

7 0
3 years ago
A particle leaves the origin with an initial velocity v = (3.00 i hat) m/s and a constant acceleration a = (-3.00 i hat - 1.400
Brilliant_brown [7]

Answer:

a)  —0.5 j m/s  

b) 4.5 i + 2.25 j m

Explanation:

<u>Givens:</u>

v_0 =3.00 i m/s

a= (-3 i — 1.400 j ) m/s^2  

The maximum x coordinate is reached when dx/dt = 0 or v_x = 0 ,thus :

<em>v_x = v_0 + at = 0  </em>

(3.00 i m/s) + (-3 i m/s^2)t=0

t = (3 m/s)/-3 i m/s^2

t = -1 s

Therefore the particle reaches the maximum x-coordinate at time t = 1 s.  

Part a The velocity-of course- is all in the y-direction,therefore:

v_y =v_0+ at

We have that v_0 = 0 in the y-direction.

v_y = (-0.5 j m/s^2)(1 s)

      = —0.5 j m/s  

Part b: While the position of the particle at t = 1 s is given by:

r=r_0+v_0*t+1/2*a*t^2

Where r_0 = 0 since the particle started from the origin.

Its position at t = 1 s is then given by :

r =(3.00 i m/s)(1 s)+1/2(-3 i — 1.400 j )(1 s)^2

 =4.5 i + 2.25 j m

8 0
3 years ago
What energy does black holes give off? A) photons B) dark matter C) dark energy D) none of the above
Umnica [9.8K]

never seen one although i guess the elegant answer is D) none of the mentioned posibilities

6 0
3 years ago
Read 2 more answers
Why a soccer ball that is quickly rolling across a grass field slows and finally stops rolling
Arturiano [62]
Friction accord while the ball was rolling in the grass and slowed it down until it finally came to a stop
5 0
3 years ago
Read 2 more answers
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