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3 years ago

9

Who was the first head of the NASA space program was Sergei Korolov, but the Russians never identified him by name. What did the

y call him in public?

1 answer:

larisa86 [58]3 years ago

6 0

Korolev's name became known in the West. I hope this helps.

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Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 2

liubo4ka [24]

Answer:

The volume of the larger cube is 5.08 g/cm³.

Explanation:

Given that,

Mass of smaller cube = 20 g

Density of smaller cube $\rho= 7.87 g/cm^2$

Dylan has two cubes of iron.

The larger cube has twice the mass of the smaller cube.

$M_{l}=2m_{s}$

Density is same for both cubes because both cubes are same material.

The density is equal to the mass divided by the volume.

$\rho=\dfrac{m}{V}$

$V=\dfrac{m}{\rho}$

Where, V = volume

m = mass

$\rho=density$

We need to calculate the volume of smaller mass

The volume of smaller mass

$V_{s}=\dfrac{m_{s}}{\rho_{s}}$

$V_{s}=\dfrac{20}{7.87}$

$V_{s}=2.54\ cm^3$

Now, We need to calculate the volume of large cube

$V_{l}=\dfrac{m_{l}}{\rho_{l}}$

$V_{l}=\dfrac{2\times20}{7.87}$

$V_{l}=5.08\ g/cm^3$

Hence, The volume of the larger cube is 5.08 g/cm³.

8 0

3 years ago

Which of the following is an exa example of a wave

maria [59]

Longitudinal waves

Transverse waves

Electromagnetic Waves

Water waves

Rope waves

LIght Waves

6 0

3 years ago

Gasoline being converted into heat energy and mechanical energy is an example of

stepan [7]

A because transforming is another name for converting

8 0

3 years ago

Given: An unbroken length of size 12 AWG conductor is looped inside a junction box so that there is more than 12 inches of free

kakasveta [241]

Answer: 27 cubic inches

Explanation:

Inch capacity for a 12 AWG=2.25

Therefore

Volume=12*2.25

=27 cubic inches

8 0

3 years ago

Two adjacent natural frequencies of an organ pipe are determined to be 986 Hz and 1102 Hz. (Assume the speed of sound is 343 m/s

ch4aika [34]

Answer:

The fundamental frequency and the length of the pipe are 115.8 Hz and 1.48 m.

Explanation:

Given that,

First frequency = 986 Hz

Second frequency = 1102 Hz

We need to calculate the length of the pipe

Using formula of length

$\Delta f=f_{2}-f_{1}=\dfrac{nv}{2L}$

Put the value into the formula

$1102-986=\dfrac{1\times343}{2\times L}$

$L=\dfrac{343}{2\times116}$

$L=1.48\ m$

We need to calculate the fundamental frequency of this pipe

$f_{1}=\dfrac{nv}{2L}$

Put the value into the formula

$f_{1}=\dfrac{1\times343}{2\times1.48}$

$f_{1}=115.8\ Hz$

Hence, The fundamental frequency and the length of the pipe are 115.8 Hz and 1.48 m.

5 0

3 years ago