Answer: The rate constant for the reaction is
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample = 559 min
a = let initial amount of the reactant =
a - x = amount left after decay process =
The rate constant for the reaction is
<u>Answer:</u> The internal energy change for the reaction is -2850 J
<u>Explanation:</u>
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
Work done for expansion process is taken as negative and work done for compression is taken as positive.
According to the First law of thermodynamics,
where,
= internal energy
q = heat absorbed or released = -2290 J
w = work done = -560 J
Putting values in above equation, we get:
Hence, the internal energy change for the reaction is -2850 J