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nekit [7.7K]
2 years ago
9

Warm air rises because of its

Chemistry
2 answers:
Nesterboy [21]2 years ago
6 0
The warm air rises because of its kinetic energy
slega [8]2 years ago
4 0

Hotter less dense then colder air as a result cold air sinks and hot air rises

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In order for substances to dissolve in water, the substances should be bonded by: ionic bonds only covalent bonds only either io
SashulF [63]
I think that it would be <span>either ionic bonds or covalent bonds</span>
5 0
3 years ago
Amantadine is effective in preventing infections caused by the influenza A virus and in treating established illnesses. It is th
Sliva [168]

Answer:

See image attached

Explanation:

a)

The full reaction mechanism of step 1 was obtained from Bartleby and attached to this answer. The steps involved in the reaction are:

1) Loss of Br- and formation of a carbocation

2) Attack of CH3CN on the carbocation

4) Formation of a quaternary nitrogen intermediate

5) Attack of water on the quaternary nitrogen intermediate

6) Loss of the water molecule

5) Formation of the amide product

b)

i) sodium hydroxide

ii) HCl

7 0
2 years ago
How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start
Nezavi [6.7K]

Answer:

18.7887 g of NaCl

Explanation:

<em>The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?</em>

Let us start by writing out the balanced equation of the reaction:

Na + Cl2 ---> NaCl2

1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.

mole = mass/molar mass

Therefore

18 g of Na = 18/23 = 0.7826 mole

23 g of Cl2 = 23/71 = 0.3239 mole

In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence

0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.

mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g

<u>Hence, 18.7887  grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.</u>

3 0
3 years ago
How many outer-shell d electrons are there in each of the following transition-metal ions?
lesya692 [45]

Answer:

The answer to your question is:

Re (III) has 5 electrons

Sc(III) =  has 1 electron

Ru(IV) =  has 6 electrons

Hg(II) = has 10 electrons

Explanation:

75 Re(III) =  1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d⁵

21 Sc(III) =   1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹

44 Ru(IV) =  1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁶

80 Hg(II) =  1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰

4 0
3 years ago
What is the sum of the coefficients for the balanced chemical equation below ?
choli [55]

Answer:

9

4X \:  +  \: 3Y _{2} \: → \: 2X _{2} Y _{3}

Sum = 4+3+2

=9

6 0
2 years ago
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