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3 years ago

If an atom with a mass of 47 amu has 22 neutrons, what atom is it?

Chemistry

1 answer:

LenaWriter [7]3 years ago

7 0

Answer:

Manganese

Explanation:

At Mass - No neutrons = Atomic Number = #protons in nucleus

47 - 22 = 25 => At. No. 25 is Manganese (Mn)

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Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:

NeTakaya

Answer:

The partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C Is 0.103 atm.

The correct option is A.

Explanation;

NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C

NH4I(s)= 0.215

NH3(g)=0.103

HI(g)Kp=0.112

Therefore = 0.103 +0.112= 0.215

Therefore the partial pressure of ammonia at equilibrium is 0.103 atm

7 0

3 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago

The mass of a deuterium nucleus 21H is less than its components masses. Calculate the mass defect.________ amu

Inessa [10]

Answer:

The mass defect of a deuterium nucleus is 0.001848 amu.

Explanation:

The deuterium is:

$^{A}_{Z}X \rightarrow ^{2}_{1}H$

The mass defect can be calculated by using the following equation:

$\Delta m = [Zm_{p} + (A - Z)m_{n}] - m_{a}$

Where:

Z: is the number of protons = 1

A: is the mass number = 2

$m_{p}$ : is the proton's mass = 1.00728 amu

$m_{n}$ : is the neutron's mass = 1.00867 amu

$m_{a}$ : is the mass of deuterium = 2.01410178 amu

Then, the mass defect is:

$\Delta m = [1.00728 amu + (2- 1)1.00867 amu] - 2.01410178 amu = 0.001848 amu$

Therefore, the mass defect of a deuterium nucleus is 0.001848 amu.

I hope it helps you!

5 0

3 years ago

Read 2 more answers

SCIENCE HELP !!!! 10 POINTS

stich3 [128]

Im working on science too!! I would help you but the attachment isn't pulling up..

5 0

3 years ago

Which statement describes the water gas particles in the air above the cup compared with the water liquid

Law Incorporation [45]

Answer:

The particles move faster and are far apart

Explanation:

A substance may exist in three states of matter; solid, liquid and gas.

In the solid state, there is very strong intermolecular forces between the particles of the substance. They can only vibrate or rotate about their mean positions but can not translate.

In the liquid state, the particles of the substance have a greater degree of freedom than in the solid. The magnitude of intermolecular forces is lower than in solids, the molecules can move at low speeds.

In a gas, the molecules are separated from each other with negligible intermolecular interaction hence they move at very high speed.

Therefore, for the water gas particles in the air above the cup; the particles move faster and are far apart.

8 0

3 years ago