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2 years ago

Solve this equation 3x + 1 = 10

Mathematics

1 answer:

slava [35]2 years ago

7 0

Steps:
1. Subtract 1 from both sides
2. 3x=9
3. Divide both sides by 3
4. Your answer is
X=3

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A movie theater is giving away a souvenir poster to any customer with a concession stand receipt that exceeds $60. The

Doss [256]

Answer:

6x + 3.5y is greater than 60

Step-by-step explanation:

Cost of x bags of popcorn = 6x

Cost of y bottles of soda = 3.5y

Total cost = 6x + 3.5y

To get a souvenir poster, this cost must exceed 60

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3 years ago

Decide if the following biconditional statement

garik1379 [7]

true because if you add up 4 90°you get 360

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2 years ago

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Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.

il63 [147K]

Answer:

The minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

Step-by-step explanation:

Given function is $f(x) = 0.15(x + 1)^2 - 3$

We need to find the maximum value or the minimum value for the function.

Now, differentiate $f(x) = 0.15(x + 1)^2 - 3$ w.r.t $x$ .

$f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\$

$f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)$

Now, we will equate $f'(x)=0$ to find critical point.

$0.3(x+1)=0\\x=-1$

Plug this critical point in to the function $f(x) = 0.15(x + 1)^2 - 3$ we get,

$f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3$

Also, $f''(x)=0.3$ which is positive, We have minimum value.

So, the minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

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3 years ago

The angle of elevation to the sun is 24°. What is the length of the shadow cast by a person 1.82 m tall? A. 0.81 m B. 1.99 m C.

Zanzabum

Answer:

C. 4.09 m

Step-by-step explanation:

Let the length of the shadow cast by a person be x m.

$\tan \: 24 \degree = \frac{height \: of \: person}{length \: of \: the \: shadow} \\ \\ 0.4452286853 = \frac{1.82}{x} \\ \\ x = \frac{1.82}{0.4452286853} \\ \\ x = 4.08778693 \: m \\ x = 4.09 \: m$

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3 years ago

(4+2n^3) + (5n^3+2)

pychu [463]

You just have to combine like terms here
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2 years ago

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