Answer:
Q = 16163.88 Joules
Explanation:
Given the following data;
Initial temperature, T1 = -25°C
Final temperature, T2 = 150°C
Mass = 45.5 g
Specific heat capacity of ice = 2.03 J/g°C
To find the quantity of heat required;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 150 - (-25)
dt = 150 + 25
dt = 175°C
Substituting into the formula, we have;
Q = 16163.88 Joules
The stock solution has a volume of 0.208L. When diluted, a stock solution with a concentration of 0.30 m clo2 becomes a 0.20 m stock solution with a volume of 0.050.
A three-dimensional space's occupied volume is measured. It is frequently measured numerically with SI-derived units (such the cubic metre and litre) or with other imperial units (such as the gallon, quart, cubic inch). Volume and length are related in how they are defined (cubed).
A highly concentrated stock solution, often prepared as a 10x concentrated solution, can be described as a stock solution since it can be diluted to create a working solution. In order to prepare complex solutions with numerous constituents, stock solutions can also be utilized as a component.
0.3M*v = 0.125M*0.50L
V=0.208L
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Density of gasoline is 0.737 g/mL and volume of tank is 13.0 gal.
Since, 1 US gal=3.78 L
Volume of tank in L will be:
Also, 1 L=1000 mL
Thus,
Mass of gasoline can be calculated as follows:
m=d×V
Here, d is density and V is volume thus,
Therefore, mass of gasoline will be 
.
