The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x
Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y
10y+ x-36=10x+y
Substitute y with 14-x
So we would get
10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5
Y=14-x
=14-5
=9
So the two digit number is
10y+x
=90+5
=95
First multiply 11 with 9 to get 99 and then 11 with d to get 11d
thus the answer is 99+11d.
<span>A) 2x -5y +z = 1
B) 3 y + 2z = 5
C) -24 z = 48
Those 3 equations you typed were somewhat squished together.
Did I retype those correctly?
Let me know and I'll solve it.
</span>
Answer:
y=3/4x-9
Step-by-step explanation:
