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3 years ago

Write 30,000,000,000 + 300,000 + 20,000 + 4 in standard form

Mathematics

2 answers:

Kryger [21]3 years ago

7 0

30,000,320,004 is the answer

Anastasy [175]3 years ago

3 0

<span>30,000,320,004 is the answer</span>

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NEED HELP PLEASE!!!!!!!!!!!!

belka [17]

Answer:

The answer is B. hope this helps

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3 years ago

A is located ( 1, -1) and B is located (4, 4) Find the coordinates of point that partition

larisa86 [58]

Answer:

5 -3

Step-by-step explanation:

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3 years ago

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Find the area of the shaded region. Round your answer to the nearest hundredth.

Anit [1.1K]

The 4 curved white corners = 1/4 of whole circle with radius 1/2×6
total white area = 4 [1/4 (pi)(3)^2] = 9pi = 28.27

So the shaded green region (S) = total square - total white area

S = 6×6 - 28.27 = 36 - 28.27 = 7.73 sq. m

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3 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

3 years ago

Consider the binomial (u^2 − v^3)^6.

Ad libitum [116K]

Answer:

The answer to your question is:

Step-by-step explanation:

(u² - v³)⁶ = u¹² - 6(u²)⁵(v³) + 15(u²)⁴(v³)² - 20(u²)³(v³)³ + 15(u²)²(v³)⁴ - 6(u²)(v³)⁵ +

(v³)⁶

= u¹² - 6u¹⁰v³ + 15u⁸v⁶ - 20u⁶v⁹ + 15u⁴v¹² - 6u²v¹⁵ + v¹⁸

a.- Find the term that contains v⁶ = 15u⁸v⁶

b.- Find the term that contains u⁶ = - 20u⁶v⁹

c.- Find the fifth term = 15u⁴v¹²

4 0

3 years ago