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frutty [35]
3 years ago
5

Four possibly winning numbers for a lottery—AB-4536, NH-7812, SQ-7855, and ZY-3221—

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0
We first of all calculate our sample size. The number of ways of generating two letter and four digits in a way that repeatition is allowed is:
26^2 x 10^4 = 676 x 10000 = 6,760,000.
Therefore, there are 6,760,000 possible number combinations for the lottery.

Probability of winning the first prize = 1/6,760,000
Probability of winning the second prize is 2/6,760,000 = 1/3,380,000
Probability of winning the third prize is 10/6,760,000 = 1/676,000
Probability of winning nothing is (6,760,000 - 13)/6,760,000 = 6,759,987/6,760,000                 *[there are 13 winnings in all]

Expected winning from the lottery = (1/6,760,000) x (100,000 - 0.33) + (1/3,380,000) x (50,000 - 0.33) + (1/676,000) x (1,000 - 0.33) + (6,759,987/6,760,000) x (-0.33) = 0.0148 + 0.0148 + 0.0015 - 0.3300 = -0.30

Therefore, the expected winning is a loss of 30 cents.
This means that it is not worth 33 cents to enter this lottery.
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