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Yakvenalex [24]
3 years ago
10

Vertical line passing through the point (6,9).

Mathematics
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

Ok and, what is the question

Step-by-step explanation:

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3 years ago
I need help with this problem and would really appreiciate a short explanation too.<br> 15 PTS
inysia [295]

okay. the point has an x and y value. place them into the equation.

1=m(1)+b

m=slope, and theequation tells you that slope is 7.

1=7(1)+b

now you need to figure out what b is.

1=7(1)+b

^

1= 7 +b

-7 -7

---------------

-6=B

b is 6. now place it into the equation, replacing the x and y values back.

y=7x-6.

write 7 and 6 in the boxes (the negative for the six has already been provided)

8 0
3 years ago
The saddest thing about betrayal is that it never comes from enemies
Xelga [282]

Answer:

you know you really need to watch what you say that comes out of your mouth

4 0
2 years ago
Read 2 more answers
Given m||n, find the value of x.<br> t<br> m<br> (2X-24)<br> (x+5)
mamaluj [8]

hope this helps

May i have brainliest

6 0
2 years ago
PLZ HELP, AND PLZ EXPLAIN
shutvik [7]

Answer:

C

Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
  • ABCD is a rhombus
  • K and L are the midpoints of sides AD and CD
  • we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

  • The pythagorian theorem !

AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

  • (AC/2)² + (BD/2)² = BC²
  • 6²+4²=52
  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

  • KL is parallel to AC
  • k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

  • KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
  • KL/12=\sqrt{52}/2*\sqrt{52}  
  • KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0
3 years ago
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