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4 years ago

Explain why an atom with 7 valence electrons and 2 energy levels has a high electronegativity and ionization energy.

Chemistry

1 answer:

boyakko [2]4 years ago

6 0

Explanation:

This atom is on the almost extreme right of the 2nd period of the periodic table (except for the stable element on the extreme right). This means it has the highest mass number of the unstable elements of the period. It thus attracts its electron clouds more strongly that the elements to the left of the period . This means it can gain an atom easily ( this is what is called electronegativity – tendency to attract an electron) than is can lose an electron. In addition, it only needs to acquire one electron to achieve a stable electron configuration (8) in its valence shell.

Due to these, it is hard for the atoms to lose an electron which is why it has a high ionization energy- the energy required to lose an electron.

Learn More:

For more on electronegativity and ionization energy check out;

brainly.com/question/13961537

brainly.com/question/13590158

brainly.com/question/539322

brainly.com/question/1594185

brainly.com/question/11743726

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Which of the following is the best description of a conversion table

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Can’t tell ya bc you didn’t list the answers

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3 years ago

Which of the following is not a property of most<br> transition metals?

saul85 [17]

Answer:

Low melting point

Explanation:

Transition metals have the following properties:

Conductivity (Electrical and Thermal)

Malleability (You can hit it with a hammer to mold it)

High melting point

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3 years ago

Read 2 more answers

The reaction between ethylene and hydrogen bromide to form ethyl bromide is carried out in a continuous reactor. The product str

iren2701 [21]

Answer:

Explanation:

The first thing to do is to write out the chemical equation showing the reaction between the two chemical compounds.

C2H4 + HBr ------------------------> C2H5Br.

The chemical species/compounds reacted in the ratio of 1 : 1 : 1. That is one mole of C2H4 reacted with one mole of HBr to give one mole of C2H5Br.

So, we are given; C2H5Br = 58.7 mol%, HBr = 18.3 mol%. Thus, for C2H4, we have [ 100 - (58.7 + 18.3)] = 23 mol%. Therefore, the limiting reagent is HBr.

So, if we have 100 mol/s ;

C2H5Br = 100 × 0.587 = 58.7 mol/s, HBr = 100 × 0.183 = 18.3 mol/s and C2H4 = 100 × 0.23 = 23 mol/s.

Therefore, the total value of the flow rate in the feed = (HBr in feed) mol/s + (C2H4 in feed) mol/s = (58.7 + 18.3)mol/s + (58.7 + 23) mol/s =( 77 + 81.7) mol/s = 158.7 mol/s. .

So, 100/158.7 × 30.5 = 192.2.

Also the feed composition in HBr and C2H4 is;

HBr = 77/158.7 = 0.4852, C2H4 = 81.7/158.7 = 0.515.

Therefore, the number of HBr in feed and C2H4 in feed = 160m/s and 200m/s respectively (approx.)

Therefore, the fraction conversion is;

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3 years ago

The molar mass of Cr(OH)2 is:

son4ous [18]

The molar mass of $Cr(OH)_2$ is 86.02 g/mole .

<h3><u> Explanation:</u> </h3>

The molar mass of a chemical compound is represented as the mass of a unit of that compound separated by the number of substances in that unit, measured in moles. The molar mass is a volume, not molecular, the property of a substance.

The molar mass is a percentage of various examples of the compound, which usually change in mass due to the appearance of isotopes.

From the below attached table, the Molar mass of $Cr(OH)_2$ is 86.0108 g/mol.