Answer:
Under the equilibrium condition
Explanation:
according to the phase rule given by Willard Gibbs, under the condition where the equilibrium between the number of phases is not affected by the gravity, electricity magnetic force or by surface action and the system is under constant temperature, pressure and concentration then the degrees of freedom(F) is proportional to the concerntration (C) and the Phases(P) at equilibrium condition.
the expression is given as : F= C-P+2
The final volume of the gas is 73.359 mL
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Given :
A sample gas has an initial volume of 72.0 mL
The work done = 141.2 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since, the process does 141.2 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm; we have
External Pressure P
:
= 783 torr × ![\frac{1 atm}{760 torr}](https://tex.z-dn.net/?f=%5Cfrac%7B1%20atm%7D%7B760%20torr%7D)
= 1.03 atm
The work done W = ![Pext V](https://tex.z-dn.net/?f=Pext%20V)
The change in volume ΔV= ![\frac{W}{Pext}](https://tex.z-dn.net/?f=%5Cfrac%7BW%7D%7BPext%7D)
ΔV = ![\frac{141.2 J \frac{1 L atm}{101.325 J} }{1.03 atm}](https://tex.z-dn.net/?f=%5Cfrac%7B141.2%20J%20%5Cfrac%7B1%20L%20atm%7D%7B101.325%20J%7D%20%7D%7B1.03%20atm%7D)
ΔV = ![\frac{0.0014}{1.03}](https://tex.z-dn.net/?f=%5Cfrac%7B0.0014%7D%7B1.03%7D)
ΔV = 0.001359 L
ΔV = 1.359 mL
The initial volume = 72.0 mL
The change in volume V is ΔV = V₂ - V₁
- V₂ = - ΔV - V₁
multiply both sides by (-), we have:
V₂ = ΔV + V₁
= 1.359 mL + 72.0 mL
= 73.359 mL
Therefore, the final volume of the gas is 73.359 mL .
Learn more about volume here:
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Answer:
Explanation:
⁵⁹₂₆Fe --------- ⁰₋₁e + ⁵⁹₂₇Co
Co- 59 is known as Cobalt
its symbol is ⁵⁹₂₇Co
The last answer, neither positive nor negative
We know that as we move from left to right across a period in a modern periodic table, electronegativity increases ( i.e., gaining of electrons from an atom ). So Magnesium(Mg) who has an atomic no. as 12 will not gain electrons but share/transfer electrons to Neon(Ne).
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