The mass of Calcium required to complete this reaction is 4.008 g.
- Law of conservation of mass states that In a closed system, mass cannot be produced or destroyed, but it can be changed from one form to another.
- The mass of the chemical constituents before a chemical reaction is equal to the mass of the constituents after the reaction.
- In several disciplines, including chemistry, mechanics, and fluid dynamics, the idea of mass conservation is widely applied.
In the given reaction mass of product after completion of reaction is 13.614 g that means total mass of constituents before reaction should also be 13.614.
So,
mass of Ca + mass of O₂ + mass of S = mass of CaSO4
Ca + 6.400 g + 3.206 g = 13.614 g
mass of Ca = 13.614 - 9.606 = 4.008 g
Therefore, by law of conservation of mass 4.008 g of Ca is required for the completion of the reaction.
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The answer is B because isotopes have the same number of protons and neutrons.
Adding or removing neutrons from the nucleus are how isotopes are created. Protons carry a positive electrical charge and they alone determine the charge of the nucleus. Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number.
They are called precipitates.
There will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.There will be needed mL of
Why?
In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:

Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:

We have that the molecular mass of the substance will be:

Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:


Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:


Now, substituting and calculating, we have:

Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.
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