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hammer [34]
3 years ago
6

Can some check if I deed this right pls ASAP

Chemistry
1 answer:
prisoha [69]3 years ago
3 0

Answer:

  1. sorry I am unable to answer
  2. because photo is not clear
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What makes up the human body? (A)many different gases (B)carbon dioxide (D)many cells (C) minerals
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Answer:

<em></em>(B) Carbon Dioxide<em></em>

Explanation:

Roughly 96 percent of the mass of the human body is made up of just four elements: oxygen, carbon, hydrogen and nitrogen, with a lot of that in the form of water. The remaining 4 percent is a sparse sampling of the periodic table of elements

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3 years ago
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Who created the onion model in chemistry?
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How many pounds does 1.00 quart of mercury weight? its density is 13.6g/mL
Gala2k [10]
Two steps by inspection 1 qt = 0.25 gallons, 13.6 g/mL = 13.6 kg/L

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5 0
3 years ago
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The atomic number of lead (Pb) is 82. Its mass number is 207. How many protons, neutrons, and electrons does this neutral atom o
AveGali [126]
An element’s atomic number is equal to the number of protons in that element’s nucleus. The mass number is the total number of an atom’s protons and neutrons. Protons have a positive charge; electrons have a negative charge; and neutrons are electrically neutral.

Putting it all together, given that the atomic number of lead is 82, the number of protons a lead atom contains is 82. The number of neutrons would be the difference between 207 and 82, or 125 neutrons. Finally, since you have a neutral atom, there must be an equal number of electrons as the number of protons—that is, 82 electrons.

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7 0
3 years ago
If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence
ValentinkaMS [17]

Answer:

M_{base}=0.173M

Explanation:

Hello there!

In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

n_{acid}=M_{base}V_{base}

Thus, by solving for the volume of the base as NaOH, we obtain:

M_{base}=\frac{n_{acid}}{V_{base}} \\\\M_{base}=\frac{0.8675g*\frac{1mol}{204.22g} }{0.02456L} \\\\M_{base}=0.173M

Best regards!

6 0
3 years ago
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