Question

Which of the following statements is true about the following reaction?

Answer 1

The correct reaction equation is:

$3NaHCO_{3} (aq) + C_{6}H_{8}O_{7} (aq) \rightarrow 3CO_{2} (g) + 3H_{2}O (l) + Na_{3}C_{6}H_{5}O_{7} (aq)$

Answer:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.

a) 22.4 L of $CO_{2}$ gas is produced only when $\frac{22.4}{3}$ L of  $C_{6}H_{8}O_{7}$ is reacted with 22.4 L of $NaHCO_{3}$. So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of $CO_{2}$  and $H_{2}O$ are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. Therefore it is correct option.

c)  $6.02\times 10^{23}$ molecules is equal 1 mole of $Na_{3}C_{6}H_{5}O_{7}$ if produced then 3 moles of $NaHCO_{3}$ is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of $H_{2}O$ (Molecular Weight of water is 18 g) is produced when 3 moles of $NaHCO_{3}$ is used but in this option only one mole of $NaHCO_{3}$ is given. So it is wrong.

Answer 2

Answer:

Connexus: A,A,A,B.

Explanation:

These are the correct answers to Chemical Calculations Lesson 2 unit 6 stoichiometry answers.

Hope this helps:)