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natali 33 [55]
3 years ago
6

What parts do all cells have?

Chemistry
2 answers:
Nonamiya [84]3 years ago
8 0

Answer:

Explanation:

apparently a nucleus is not among one of these common parts, living environmet never taught me that, i find that interseting. anyways heres the answer, it made me write an explanation lol

levacccp [35]3 years ago
6 0

Answer:

All cells have these four parts in common: a plasma membrane, cytoplasm, ribosomes, and DNA

Explanation:

an i get brainliest plz

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Hsvsusvshssveuevsjsvsjdvsudvysvwkwhsjwvsgsbkwbsywvejwvsh​
dybincka [34]

Sorry, I won't understand your words.

6 0
3 years ago
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Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife​
yuradex [85]

Answer:

\boxed{\text{2408 min}}

Explanation:

The integrated rate law for radioactive decay is

\ln\dfrac{N_{0}}{N_{t}} = kt

1. Calculate the decay constant

\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

8 0
3 years ago
What is 2KNO3 + 1H2CO3 = 1K2CO3+2HNO3 reaction type
Tema [17]
DR is the correct answer

hope this helps
4 0
2 years ago
For the reaction of aqueous strontium chloride and lithium sulfate, write the balanced molecular equation
Igoryamba
SrCl2 + Li2(SO4) —> 2LiCl + Sr(SO4)
7 0
3 years ago
The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 1
IgorC [24]

The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

<h3>Effect of Pressure on Solubility </h3>

As the <em>pressure </em>of a gas increases, the <em>solubility </em>increases, and as the <em>pressure </em>of a gas decreases, the <em>solubility </em>decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }

Where S_{1} is the initial solubility

P_{1} is the initial pressure

S_{2} is the final solubility

P_{2} is the final pressure

From the given information

S_{1} = 0.890 \ g/L

P_{1} = 120 \ kPa

P_{2} = 100 \ kPa

Putting the parameters into the formula, we get

\frac{0.890}{120}=\frac{S_{2}}{100}

S_{2}= \frac{0.890 \times 100}{120}

S_{2}= 0.742 \ g/L

Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Learn more on Solubility here: brainly.com/question/4529762

7 0
2 years ago
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