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3 years ago

A dog walks a distance of 55.5 meters in 120 seconds. What was its speed?

Physics

1 answer:

Nitella [24]3 years ago

8 0

Answer: ...

Explanation: 1: The dog is walking 0.4625MPS (Meters per second. M/S)

To calculate speed you divide the distance by time so 55.5 Meters/120 Seconds is 0.4625 MPS

2: The car traveled 15 KM

To calculate speed you need to multiply the speed by time. (Since it's multiplication it can be put in any order) So 600 Secondsx25 Meters is 15,000 M which is 15 KM.

3: It would take 8 Minutes and 20 Seconds to travel 1500 Meters.

To calculate the time you multiply Speed by distance (Order doesn't count.)

So 1500 Metersx3 MPS is 8 Minutes and 20 seconds.

4: It was going 2.7775 MPS.

To calculate the speed you divide the distance over time. So 9999 Meters/3600 seconds is 2.7775 MPS.

5: It was going 1.1222... (Infinite)

To calculate the speed you divide the distance over time

So 8080 Meters/ 7200 Seconds is 1.222...

6: It would cover 1.375 Meters.

To calculate the Distance you multiply Speed by time (Order doesn't count.)

So 10.25 Secondsx5.5 MPS is 1.375 Meters.

7: It would take 1 Minute and 31 Seconds to travel 10 Meters.

To calculate the time you multiply Speed by distance (Order doesn't count.)

So 10 Metersx0.11 MPS is 1 Minute and 31 seconds

Hopes this helps because this took over 10 minutes.

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2 years ago

What is the fault-current circuit breaker? Describe its function.

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Answer:

A circuit breaker is a switching mechanism that interrupts the current that is irregular or fault. It is a mechanical system that interferes with high magnitude (fault) current flow and also performs a transfer operation. Hope this helps :)

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3 years ago

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Armand hands the rock to Pierre, who is standing next to the trampoline. Explain how Armand moves, in terms of the forces acting

Nikolay [14]

Answer:

Armando's weight ,restored force created by the trampoline

a harmonic movement within the trampoline

Explanation:

In a trampoline we have two forces that actuate Armando's weight and the restored force created by the trampoline that depends on the deformation distance of the elastic canvas.

Amando's weight is vertical and directed towards the center of the Earth and has a constant value, this weight is balanced with the elastic force the springboard exerts on Armando in a vertical direction.

In general, when entering the trampoline, a small jump is made, this creates a speed that deforms the canvas until the speed is reduced to zero, at this point the elastic force is greater than the weight and the boy begins to climb, After the boy leaves the canvas he meets only the force of gravity and his speed decreases to zero and begins his fall.

In Summary Armando is in a harmonic movement within the trampoline

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3 years ago

A 97.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.63 r

sammy [17]

Answer:

the final angular velocity of the platform with its load is 1.0356 rad/s

Explanation:

Given that;

mass of circular platform m = 97.1 kg

Initial angular velocity of platform ω₀ = 1.63 rad/s

mass of banana $m_{b}$ = 8.97 kg

at distance r = 4/5 { radius of platform }

mass of monkey $m_{m}$ = 22.1 kg

at edge = R

R = 1.73 m

now since there is No external Torque

Angular momentum will be conserved, so;

mR²/2 × ω₀ = [ mR²/2 + $m_{b}$ ( $\frac{4}{5}$ R)² + $m_{m}$ R² ]w

m/2 × ω₀ = [ m/2 + $m_{b}$ ( $\frac{4}{5}$ )² + $m_{m}$ ]w

we substitute

w = 97.1/2 × 1.63 / ( 97.1/2 + 8.97(16/25) + 22.1

w = 48.55 × [ 1.63 / ( 48.55 + 5.7408 + 22.1 )

w = 48.55 × [ 1.63 / ( 76.3908 ) ]

w = 48.55 × 0.02133

w = 1.0356 rad/s

Therefore; the final angular velocity of the platform with its load is 1.0356 rad/s

8 0

2 years ago

0.0884 moles of a diatomic gas

Sloan [31]

Answer:

W = - 118.24 J (negative sign shows that work is done on piston)

Explanation:

First, we find the change in internal energy of the diatomic gas by using the following formula:

$\Delta\ U = nC_{v}\Delta\ T$

where,

ΔU = Change in internal energy of gas = ?

n = no. of moles of gas = 0.0884 mole

Cv = Molar Specific Heat at constant volume = 5R/2 (for diatomic gases)

Cv = 5(8.314 J/mol.K)/2 = 20.785 J/mol.K

ΔT = Rise in Temperature = 18.8 K

Therefore,

$\Delta\ U = (0.0884\ moles)(20.785\ J/mol.K)(18.8\ K)\\\Delta\ U = 34.54\ J$

Now, we can apply First Law of Thermodynamics as follows:

$\Delta\ Q = \Delta\ U + W$

where,

ΔQ = Heat flow = - 83.7 J (negative sign due to outflow)

W = Work done = ?

Therefore,

$-83.7\ J = 34.54\ J + W\\W = -83.7\ J - 34.54\ J\\$

<u>W = - 118.24 J (negative sign shows that work is done on piston)</u>

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3 years ago

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