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3 years ago

A dog walks a distance of 55.5 meters in 120 seconds. What was its speed?

Physics

1 answer:

Nitella [24]3 years ago

8 0

Answer: ...

Explanation: 1: The dog is walking 0.4625MPS (Meters per second. M/S)

To calculate speed you divide the distance by time so 55.5 Meters/120 Seconds is 0.4625 MPS

2: The car traveled 15 KM

To calculate speed you need to multiply the speed by time. (Since it's multiplication it can be put in any order) So 600 Secondsx25 Meters is 15,000 M which is 15 KM.

3: It would take 8 Minutes and 20 Seconds to travel 1500 Meters.

To calculate the time you multiply Speed by distance (Order doesn't count.)

So 1500 Metersx3 MPS is 8 Minutes and 20 seconds.

4: It was going 2.7775 MPS.

To calculate the speed you divide the distance over time. So 9999 Meters/3600 seconds is 2.7775 MPS.

5: It was going 1.1222... (Infinite)

To calculate the speed you divide the distance over time

So 8080 Meters/ 7200 Seconds is 1.222...

6: It would cover 1.375 Meters.

To calculate the Distance you multiply Speed by time (Order doesn't count.)

So 10.25 Secondsx5.5 MPS is 1.375 Meters.

7: It would take 1 Minute and 31 Seconds to travel 10 Meters.

To calculate the time you multiply Speed by distance (Order doesn't count.)

So 10 Metersx0.11 MPS is 1 Minute and 31 seconds

Hopes this helps because this took over 10 minutes.

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The current theory of the structure of the Earth, called plate tectonics, tells us that the continents are in constant motion.

lesya [120]

Answer:

(a) m = 1.6 x 10²¹ kg

(b) K.E = 2.536 x 10¹¹ J

Explanation:

(a)

First we find the volume of the continent:

V = L*W*H

where,

V = Volume of Slab = ?

L = Length of Slab = 4450 km = 4.45 x 10⁶ m

W = Width of Slab = 4450 km = 4.45 x 10⁶ m

H = Height of Slab = 31 km = 3.1 x 10⁴ m

Therefore,

V = (4.45 x 10⁶ m)(4.45 x 10⁶ m)(3.1 x 10⁴ m)

V = 6.138 x 10¹⁷ m³

Now, we find the mass:

m = density*V

m = (2620 kg/m³)(6.138 x 10¹⁷ m³)

m = 1.6 x 10²¹ kg

(b)

The kinetic energy will be:

K.E = (1/2)mv²

where,

v = speed = (1 cm/year)(0.01 m/1 cm)(1 year/365 days)(1 day/24 h)(1 h/3600 s)

v = 3.17 x 10⁻¹⁰ m/s

Therefore,

K.E = (1/2)(1.6 x 10²¹ kg)(3.17 x 10⁻¹⁰ m/s)²

K.E = 2.536 x 10¹¹ J

(c)

For the same kinetic energy but mass = 77 kg:

K.E = (1/2)mv²

2.536 x 10¹¹ J = (1/2)(77 kg)v²

v = √(2)(2.536 x 10¹¹ J)

v = 7.12 x 10⁵ m/s

7 0

3 years ago

How can you use a magnet to induce a current?

Furkat [3]

A coil of wire with a current flowing thru it becomes a magnet

3 0

3 years ago

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Ron fills a beaker with glycerin (n = 1.473) to a depth of 5.0 cm. if he looks straight down through the glycerin surface, he wi

Tju [1.3M]

By law of refraction we know that image position and object positions are related to each other by following relation

$\frac{\mu_1}{h_o} = \frac{\mu_2}{h_i}$

here we know that

$\mu_1 = 1.473$

$h_o = 5 cm$

$\mu_2 = 1$

now by above formula

$\frac{1.473}{5} = \frac{1}{h_i}$

$h_i = 3.39 cm$

so apparent depth of the bottom is seen by the observer as h = 3.39 cm

7 0

3 years ago

Calculate delta g for the reaction if the partial pressures of the initial mixture are pcl5 = .0029 atm, pcl3 = .27 atm, and pcl

AnnyKZ [126]

Answer: equation for the reaction is given below

PCL2+PCL3=PCL5

Where pcl2=0.40atm,pcl3=0.27atm

Pcl5=0.0029atm

Using ∆G=-RTin(PCL5/PCl2*PCL3)

Where R=8.314J/K/mol and T=298K

∆G=-8.314*298in(0.0029/0.40*.27)

∆G=8962.6J/mol

Explanation:

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3 years ago

A 3.8 kg object is lifted 12 meters. approximately how much work is performed during the lifting.

Dmitry [639]

work done=446.9 J . so option (c) is correct.

Explanation:

the formula for work done is given by

W= F d

F= force= mg where m= mass and g= acceleration due to gravity

F= 3.8 (9.8)=37.24 J

so W=37.24 (12)

W=446.9 J

7 0

3 years ago

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