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riadik2000 [5.3K]
3 years ago
7

A. How does the speed of light in a vacuum change when observed from two different frames of reference?

Physics
2 answers:
Katyanochek1 [597]3 years ago
5 0

Answer:

a) The velocity of the light is invariant, this means that is always the same independent of the frame in which you are looking.

b) Inertial frames, this means that the frame is "not accelerating" (it can be fixed in place or moving with constant velocity)

C) When you are in the train, you are in the same frame than the clock, so you will no see nothing interesting, now, if you are outside of the train you will see a time dilation, this means that each "tick" of the clock is slightly longer than the one that the observer is holding. This happens because of the invariance of the speed of light, a way of seeing it is the next:

Suppose that the clock works sending a light signal, it travels a distance "d", it rebounds in a surface and comes to a receptor, when the photon hits the receptor, a "tick" of the clock is recorded, which would mean that a second has passed.

If the clock is still, the photon travels the distance d two times at a velocity c, so the "tick" of the clock is each "2d/c" seconds.

Now, in the moving clock, the distance that the photon moves is slightly higher (because now it also moves with the clock) suppose that this distance is D, so now the time is "2D/c", which will be bigger than the one that we had before.

anyanavicka [17]3 years ago
4 0

a) It is absolute, so it does not change.

b) Inertial ones.

c) Inside the train the time will slow down relatively to the outside clock. So if one travel at nearly the speed if light for 2 hours on his clock, for outdoor observers it will look like 3 hours.

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saul85 [17]

Answer:

  t = 0.714 s and  x = 5.0 m

Explanation:

This is a projectile throwing exercise, in this case when the skater leaves the bridge he goes with horizontal speed

         vₓ = 7.0 m / s

Let's find the time it takes to get to the river

         y = y₀ + v_{oy} t - ½ g t²

the initial vertical speed is zero and when it reaches the river its height is zero

        0 = y₀ + 0 - ½ g t²

        t = \sqrt{\frac{2y_o}{g}  }

        t = ra 2 2.5 / 9.8

        t = 0.714 s

the distance traveled is

       x = vₓ t

       x = 7.0 0.714

       x = 5.0 m

3 0
3 years ago
When a force causes an object to move in the direction of the force blank occurs
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Its magnetic..........ig

7 0
3 years ago
What measures the distance between two consecutive crests of a wave?
Marina86 [1]
Answer A is incorrect
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B  is incorrect
A trough is just 1 point. It is not the distance between 2 troughs.

C is incorrect.
the amplitude measures the height of a crest from the middle of the wave to the crest (or trough).

D is the correct answer. That is the distance between 2 crests or 2 troughs 
8 0
3 years ago
A 1060-kg car moving west at 16 m/s collides with and locks onto a 1830-kg stationary car. determine the velocity of the cars ju
iren [92.7K]
M1U1 + M2V2 = (M1+M2)V, where M1 is the mass of the moving car, M2 is the mass of the stationary car, U1 is the initial velocity, and V is the common velocity after collision.
therefore; 
(1060× 16) + (1830 ×0) = (1060 +1830) V
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      V = 5.869 m/s
The velocity of the cars after collision will be 5.689 m/s
5 0
3 years ago
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