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Nastasia [14]
3 years ago
5

How much WATER needed to offset the force of jumping down from 20metre in vacuum environment,to keep me alive.

Physics
1 answer:
kenny6666 [7]3 years ago
6 0

Answer:

it's quite difficult

Explanation:

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A radio controlled car rolls 10 m south,then reverse direction and rolls 8m north.The car has traveled a distance of 18 m and ha
Snezhnost [94]

Answer:

The total displacement of the car is 2 meters south

Explanation:

As the car went south 10m, and then went back over it initial path for 8 meters, the actual distance registered in the car's odometer will be 18 m, but as far as vector displacement in its final position, this will be 2 meters south (10m -8m=2m).

Notice that the displacement vector is defined as the final position minus the initial position, which gives a distance of 2 from the origin, in the suoth direction.meters

6 0
3 years ago
Hurryyy please helppp <br> Select all of the objects Found in our solar system
kipiarov [429]

Answer:  Star, planets, dwarf planets, comets, asteroids.

4 0
4 years ago
Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest
Alex Ar [27]

We have that the see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

From the Question we are told that

Wan’s mass is M_w=45 kg

Nurul’s mass is M_n= 30 kg.

Generally

The Will be balance when the weight on both sides of the see-saw are equal

M_w=M_n+x

45=30+x

x=45-30

x=15kg

In conclusion

The see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

For more information on this visit

brainly.com/question/22255610

5 0
3 years ago
When placed 1.18 m apart, the force each exerts on the other is 11.2 N and is repulsive. What is the charge on each
aleksandr82 [10.1K]

Answer:

q=41.62\ \mu C

Explanation:

Given that,

Force between two objects, F = 11.2 N

Distance between objects, d = 1.18 m

We need to find the charge on each objects. The force between charges is as follows :

F=\dfrac{kq^2}{r^2}\\\\q=\sqrt{\dfrac{Fr^2}{k}} \\\\q=\sqrt{\dfrac{11.2\times (1.18)^2}{9\times 10^9}} \\\\q=41.62\ \mu C

So, the charge on each sphere is 41.62\ \mu C.

7 0
3 years ago
What would be Kelley's weight be in newtons if her mass was 70 kilograms
ad-work [718]

Answer:

Kelly's weight would be 688.47 Newtons.

Explanation:

1 Kilogram would be 9.81 Newtons.

8 0
3 years ago
Read 2 more answers
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