Answer:
a) fr = 224.3 N
, b) fr = 224.3 N
, c) v = 198.0 m/s
Explanation:
a) For this exercise let's start by calculating the acceleration in the fall
v² = v₀² - 2 a (y-y₀)
When it jumps the initial vertical speed is zero
a = -v² / 2 (y-y₀)
a = -68 2/2 (1000-2000)
a = 2,312 m / s²
Let's use the second net law to enter the average friction force
fr = m a
fr = 97 2,312
fr = 224.3 N
b) let's look for acceleration
v² = v₀² - 2 a y
a = (v² –v₀²) / 2 (y-y₀)
a = (4² - 68²) / 2 (0-1000)
a = 2,304 m / s²
fr = m a
fr = 97 2,304
fr = 223.5 N
c) the speed of the wallet is searched with kinematics
v² = v₀² - 2 g (y-y₀)
v = √ (0-2 9.8 (0-2000))
v = 198.0 m/s
Answer:
675J
Explanation:
Given parameters:
Force = 45N
Distance = 15m
Unknown:
Work done by Sheila = ?
Solution:
Work done by a body is the amount of force applied to make a body move through a distance;
Work done = Force x distance
Now;
Work done = 45 x 15 = 675J
soy de texas, united states
Answer:
The answer to your question is the letter A) F = 9.23 x 10⁻⁷ N
Explanation:
Data
q₁ = -6.25 x 10⁻⁹ C
q₂ = -6.25 x 10⁻⁹ C
d = 0.617 m
k = 9 x 10⁹ Nm²/C²
F = ?
Formula
F = k q₁q₂ /r²
-Substitution
F = (9 x 10⁹)(-6.25 x 10⁻⁹)(-6.25 x 10⁻⁹) / (0.617)²
-Simplification
F = 3.512 x 10⁻⁷ / 0.381
-Result
F = 9.227 x 10⁻⁷ N ≈ 9.23 x 10⁻⁷ N
Answer:
D. Humidity refers to the amount of water vapor in the air
