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zaharov [31]
3 years ago
7

Solve equation m Divided by 4+6=3

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Answer:

m= -3/4

Step-by-step explanation:

m÷4+6= 3

m÷4= 3-6

m÷4= -3

m= -3/4

You might be interested in
A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.
Verdich [7]

Answer:

2a - 3b + 4c = 1

Step-by-step explanation:

Given

a^2 + b^2 + c^2 = 2(a - b - c) - 3

Required

Determine 2a - 3b + 4c

a^2 + b^2 + c^2 = 2(a - b - c) - 3

Open bracket

a^2 + b^2 + c^2 = 2a - 2b - 2c - 3

Equate the equation to 0

a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0

Express 3 as 1 + 1 + 1

a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0

Collect like terms

a^2 - 2a + 1 + b^2 + 2b + 1 + c^2  + 2c + 1 = 0

Group each terms

(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

Factorize (starting with the first bracket)

(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b^2 + 2b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b^2 + b+b + 1) + (c^2  + 2c + 1) = 0

((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)(b + 1)) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c^2  + 2c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c^2  + c+c + 1) = 0

((a - 1)^2) + ((b + 1)^2) + (c(c  + 1)+1(c + 1)) = 0

((a - 1)^2) + ((b + 1)^2) + ((c  + 1)(c + 1)) = 0

((a - 1)^2) + ((b + 1)^2) + ((c  + 1)^2) = 0

Express 0 as 0 + 0 + 0

(a - 1)^2 + (b + 1)^2 + (c  + 1)^2 = 0 + 0+ 0

By comparison

(a - 1)^2 = 0

(b + 1)^2 = 0

(c  + 1)^2 = 0

Solving for (a - 1)^2 = 0

Take square root of both sides

a - 1 = 0

Add 1 to both sides

a - 1 + 1 = 0 + 1

a = 1

Solving for (b + 1)^2 = 0

Take square root of both sides

b + 1 = 0

Subtract 1 from both sides

b + 1 - 1 = 0 - 1

b = -1

Solving for (c  + 1)^2 = 0

Take square root of both sides

c + 1 = 0

Subtract 1 from both sides

c + 1 - 1 = 0 - 1

c = -1

Substitute the values of a, b and c in 2a - 3b + 4c

2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)

2a - 3b + 4c = 2 +3  -4

2a - 3b + 4c = 1

7 0
4 years ago
A pet store was selling 4 lizards for $47.88. If they ended up selling 6 lizards, how much would they have earned?
fgiga [73]

Answer:

Step-by-step explanation:

Step one- Find out how much it costs for one Lizard In this case, for four lizards it costs $47.88. To find the price for one lizard you divide 47.88 by four

$47.88/4Lizards=$11.97 per lizard.

Step two- Now that we have the price for one lizard, your question asks you how much for 6 lizards. We need to find that cost. To do so you multiply $11.97 by 6 for the lizards.

Your answer is $71.82

Hope This Helped :)

4 0
3 years ago
Read 2 more answers
Someone help me with this pls
Mumz [18]

Answer:

There will be approx 283908 hits.

Step-by-step explanation:

A website had 342,000 hits in 2011.

This is a decline of 2.3% from the previous year.

Decline rate = 2.3% or 0.023

So, increase rate will be 1-.023=0.977

Time = 2019-2011=8

We can calculate the answer as:

342000\times(0.977)^{8}

= 342000\times0.83014

= 283907.88 rounding to 283908.

Therefore, there will be approx 283908 hits.

4 0
4 years ago
One number is 6 more than twice another. If their sum is 51, find the numbers.
joja [24]

Answer:

y=2x+6 ; x+y=51

Step-by-step explanation:

assuming x is one number and y is the other -

one number (y) is 6 more (+6) than twice another (2x) -

using that knowledge we form an equation -

y=2x+6

the sum (x+y) is 51

using this knowledge we can make the equation -

x+y=51

now you have -

y=2x+6 or 2x-y=-6

x+y=51

using system of equations -

you add the equations -

3x=45

x=15

y=51-x => y=36

hope this helps!!

7 0
3 years ago
A robot can complete 4 tasks in 3/5 hour. Each task takes the same amount of time. a. How long does it take the robot to complet
egoroff_w [7]

Answer:

A. It takes the robot 3/20 hour to complete one task

B. The robot can complete 6 2/3 task in on hour

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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