Answer:
Energy is transformed from potential to kinetic and vice versa
Explanation:
The energy is transformed from mechanical to kinetic energy when the object changes its position with respect to a reference point, where it loses height but increases its speed. When the object is at maximum height with respect to a reference point, it will have its maximum potential energy value. When the object passes through the reference point it will have potential energy equal to zero, but this energy will become kinetic energy.
The most characteristic and real example is that of a pendulum at one end, as can be seen in the attached image.
When the pendulum is located at the top end, as shown in Figure 1, at that point the maximum potential energy will be held. Then the pendulum is released and when it passes through the reference point and its height is zero, with respect to that point, all potential energy will have become kinetic energy in the same way at this point the maximum speed of the pendulum will be set.
Based on the options given, the answer is two waves subtract from each other. Destructive interference happens when two waves meet each other however with different frequencies cancel each other out.
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The book Two New Sciences is the book that would later influence Sir Isaac Newton
Answer:
The diameter of the camera aperture must be greater than or equal to 1.49m
Explanation:
Let the distance separating two objects, x = 6.0 cm = 0.06 m
The distance between the observer and the two objects, d = 160 km = 160000 m
Let ∅ = minimum angular separation between the two objects that the satellite can resolve
tan( ∅) = x/d
Since there is minimum angular separation, tan( ∅) ≈∅
∅ = x/d
∅ = 0.06/160000
∅ = 3.75 * 10⁻⁷rad
For the satellite to be able to resolve the objects,
D ≥ 1.22λ/∅
λ = 560 nm = 560 * 10⁻⁹
D ≥ 1.22 * (560 * 10⁻⁹)/(3.75 * 10⁻⁷)
D ≥ 149.33 * 10⁻² m
D ≥ 1.49 m
Answer:
61.105 C
Explanation:
Charge: This can be defined as the product of current flowing through a circuit and time. The S.I unit of charge is coulomb's (C)
I = Q/t ................. Equation 1
Where I = current, Q = Charge, t = time.
Note: The current through a cross sectional area of the compressor is the amount of charge passing through the area per unit time.
Q = It ............... Equation 2
Given: I = 121 A, t = 0.505 A.
Substitute into equation 2
Q = 121(0.505)
Q = 61.105 C.
Hence the charge passing through the cross sectional area of the circuit = 61.105 C
