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3 years ago

8

Help me with this please help me asp

2 answers:

Igoryamba3 years ago

7 0

Supplementry angle That's cool you go to k12 online homeschool

igomit [66]3 years ago

4 0

<1 and <2 are vertical angles (last choice)

hope it helps

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(picture)<br>complete it

Brrunno [24]

Answer:

749, 715, 710

Step-by-step explaination:

8 0

2 years ago

4(x+1.5)=38 solve for x

Kitty [74]

Answer:

x = 8

Step-by-step explanation:

4(x+1.5)=38

Distribute the 4

4x +6 = 38

Subtract 6 from each side

4x+6-6 = 38-6

4x = 32

Divide each side by 4

4x/4 = 32/4

x = 8

3 0

3 years ago

Trey needs to estimate 678 + 395. He adds 678 and 395 and gets 1073. He rounds that to the nearest hundred to get 1100. What was

mina [271]

Answer:

A).

Step-by-step explanation:

There are no decimals so it cannot be option c or d

Hope this helps

5 0

2 years ago

Read 2 more answers

Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

Dont forget that the square is also a rectangle.

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28%20%20%7B81%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%29%5E%7B4%7D%20" id="TexFormula1" tit

Sveta_85 [38]

If you're asking how to simplify, then this is how you do it.

when a power meets another power but in brackets, then you have to multiply the powers. ¼ × 4 would be 1. i simplified 81 to 3⁴.

7 0

3 years ago