Ask question

Ask question

All categories

3 years ago

8

A cylindrical coil of radius 6 cm is placed in magnetic field, which is changing in time with the rate 0.5 T/s. The magnetic fie

ld direction is parallel to the cylinder axis. What should be the number of turns in the coil to induce the emf

1 answer:

Jlenok [28]3 years ago

3 0

induced emf value is missing..

please correct the question

You might be interested in

Low-pressure areas tend to ____ before occluding and ____ after occluding

alexgriva [62]

Out of the following given choices;

a. decelerate; accelerate

b. accelerate; decelerate

c. stop; accelerate

d. decelerate; stop

<span>The answer is B. This is because the cold front usually rotates around the warm front as cold air mass coverage in the low-pressure system. This causes the cold air mass to accelerate to catch up with the warm front. When an occluded front ( that is the boundary that separates the older cool air mass already in place from new incoming cold air mass), that the system decelerates. </span>

4 0

4 years ago

Calculate the acceleration of a bus that speed up from 20ms-1 to 40ms-1 in 8 seconds?

Anastaziya [24]

Answer:

2.5 ms^-2

Explanation:

acceleration

= (final velocity - initial velocity)/time

= [(40m/s) - (20m/s)]/8s

= (20m/s)/8s

= 5/2 m/s²

= 2.5 m/s²

= 2.5 ms^-2

3 0

3 years ago

Any child is pushing a shopping cart at a speed of 1.5 m/s.how long will it take this child to push the cart down the aisle with

NARA [144]

1.5 m/s is the velocity. 9.3 m is the length of aisle, over which Distance will be covered. Time is demanded in which the child will move the cart over the aisle with 1.5 m/s. v=S/t and, t=S/v Put values, t=9.3/1.5=6.2 s

7 0

3 years ago

HOW DID PEOPLE SURVIVE IN THE YEARS of Paleolithic &The Metal Ages

Lorico [155]

Answer:

By gathering plants, fishing, and hunting or scavenging wild animals. They used knapped stone tools, and also used wood and bone tools. Please vote Brainliest!

Explanation:

4 0

3 years ago

Read 2 more answers

A 60 g ball is dropped from rest from a height of 2.4 m. It bounces off the floor and rebounds to a maximum height of 1.9 m. If

kap26 [50]

Answer:

The force is 1.34 newtons and its direction is upward.

Explanation:

Choosing positive direction pointing towards the floor in this collision we're going to use the momentum-impulse theorem that states:

$J=\Delta p$ (1)

with $\Delta p=p_f-p_i$ the change in the momentum and J the impulse, with pi the initial momentum that is the momentum just before the collision and pf the final momentum th is the momentum just after the collision. The impulse J is also defined as:

$J=F_{avg}\Delta t$ (2)

with $F_{avg}$ the average force and $\Delta t$ the time the collision lasts

We can equate expressions (2) and (1):

$\Delta p=p_f-p_i=F_{avg}\Delta t$

Using the definition of linear momentum as mass (m) time velocity (v):

$mv_f-mv_i=F_{avg}\Delta t$

We can solve for Favg:

$F_{avg}=\frac{m(v_f-v_i)}{\Delta t}$ (3)

Now we should find the velocities vf and vi, we should do this using conservation of energy:

For the velocity the ball has just before reaches the floor:

$U_i=K_f$

With Ui the initial potential energy (there is not initial kinetic energy) and Kf the final kinetic energy (there is not final potential energy), then:

$mgh=\frac{mv_i^2}{2}$

solving for vi:

$v_i=\sqrt{2gh}=\sqrt{2*9.81*2.4}=6.86\frac{m}{s}$

For the velocity the ball has just after bounces the floor:

$K_i=U_f$

There is not initial potential energy because it's a floor level at this instant, and the there is not final kinetic energy because the ball has instantly zero velocity at its maximum height (hm), then:

$\frac{mf_i^2}{2}=mgh_m$

solvig for vf:

$v_f=\sqrt{2gh_m}=\sqrt{2*9.81*1.9}=6.10\frac{m}{s}$

Using vf and vi on (3):

$F_{avg}=\frac{(0.06)(6.10-6.86)}{0.034}=-1.34 N$

The negative sign indicates the direction of the force is pointing away the floor

4 0

3 years ago