Exothermich cools and endo heats so it heats
For this case, the first thing you should know is that the length of a football field is around 100 meters.
We must then look for a measure close to this value.
We have the following unit conversion:
1 meter = 10 decimeters
Applying the conversion we have:

Therefore, the measure closest to a soccer field is:
1000 dm
Answer:
The length of a football field is closest to:
(2) 1000 dm
Answer:
D) the second at the doorknob
Explanation:
The torque exerted by a force is given by:

where
F is the magnitude of the force
d is the distance between the point of application of the force and the centre of rotation
is the angle between the direction of the force and d
In this problem, we have:
- Two forces of equal magnitude F
- Both forces are perpendicular to the door, so 
- The first force is exerted at the midpoint of the door, while the 2nd force is applied at the doorknob. This means that d is the larger for the 2nd force
--> therefore, the 2nd force exerts a greater torque
Answer:
43.96 L
Explanation:
We are given that





We know that


Substitute the values


Hence, the volume of balloon at -14.8 degree Celsius=43.96 L