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hjlf
2 years ago
11

Write a paragraph comparing one bulb in series, two bulbs in series, and two bulbs in parallel. What did you learn?

Physics
1 answer:
Kaylis [27]2 years ago
7 0

the 2 lightbulbs in series on has one path so it produces  less light. The bulbs in parallel has two lightbulbs but two different paths so it produces more light. (i can make it longer if you want )

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What does the area between the line and the x axis represent on a velocity vs time graph
pychu [463]

the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period

Thank you

5 0
3 years ago
1 point
Sav [38]

Answer:

388.5J

Explanation:

Given parameters:

Weight  = 70N

Height  = 5.55m

Unknown:

Gravitational potential energy at the top of the ladder  = ?

Solution:

The gravitational potential energy is the energy due to the position of the body.

  Gravitational potential energy  = Weight x height

So;

 Gravitational potential energy  = 70 x 5.55 = 388.5J

8 0
2 years ago
The "Giant Swing" at a county fair consists of a vertical central shaft with a number of horizontal arms attached at its upper e
Mashcka [7]

Answer:

Explanation:

When the central shaft rotates , the seat along with passenger also rotates . Their rotation requires a centripetal force of mw²R where m is mass of the passenger and w is the angular velocity and R is radius of the circle in which the passenger rotates.

This force is provided by a component of   T , the tension in the rope from which the passenger hangs . If θ be the angle the rope makes with horizontal ,

T cos θ will provide the centripetal force . So

Tcosθ = mw²R

Tsinθ component will balance the weight .

Tsinθ = mg

Dividing the two equation

Tanθ = \frac{g}{\omega^2R}

Hence for a given w , θ depends upon g or weight .

8 0
3 years ago
Read 2 more answers
calculate the diameter of a silver wire of length 75cm , which is extended by 1.85mm when a 10kg mass is suspended from it's end
sdas [7]

Answer:0.8\ mm

Explanation:

Given

length of wire l=75\ cm

change in length \Delta l=1.85\ mm

mass of wire m=10\ kg

Young's modulus for silver E=7.9\times 10^{10}\ N/m^2

load on wire F=mg

F=10\times 9.8=98\ kg

change in length is given by

\Delta l=\dfrac{Pl}{AE}

Where A=area of cross-section

A=\dfrac{Pl}{\Delta lE}

A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}

A=\dfrac{73.5}{14.615\times 10^{7}}

A=5.029\times 10^{-7}\ m^2

also wire is the shape of cylinder so cross-section is given by

A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2

\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }

\Rightarrow d^2=64.02\times 10^{-8}

\Rightarrow d=8\times 10^{-4}\ m

\Rightarrow d=0.8\ mm

4 0
3 years ago
The elements least likely to form bonds are found in which group?<br> O 15<br> O 16<br> 017<br> O 18
12345 [234]
The answer is group 18.

Explanation:
Group 18 is known as the Noble Gases. They are the most stable elements because they have a full outer shell of valence electrons, so they have no need to bond with other elements.
7 0
3 years ago
Read 2 more answers
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