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forsale [732]
3 years ago
12

A marble is placed at Location W. When the marble is released, it rolls down the track.

Physics
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

Z

Explanation:

Nataly [62]3 years ago
3 0

Answer:

The Answer Is Z,

Explanation:

Also Here Is A Picture Of My Teacher Being Frozen:

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PLEASE HELP SEE PART 2 FOR MORE INFO
Angelina_Jolie [31]

Answer:

This question cannot be answered

Explanation:

This is a practical experiment which can only be done in person. Kindly go through the instructions and do the experiment carefully.

8 0
3 years ago
After hearing about an accident on his normal route, Mr. Gujral checks for alternate routes to get to work. What type of circuit
shtirl [24]

Answer:

C

Explanation:

a parallel circuit because there is more than one path

3 0
3 years ago
How do molecules at warm temperatures differ from molecules at cool temperatures? Question 1 options: At warm temperatures, mole
yaroslaw [1]

Answer:

A. At warm tempetures, molecules move around more.

Explanation:

I'm at k12 and I just took the test got it right. Physical Science: Unit 2 Test

7 0
3 years ago
Read 2 more answers
Describe how electromagnetic waves are formed and travel through space.
Maslowich

Answer:

Electromagnetic waves are created by a charged particle that generates an electric field. The electric field creates a magnetic field. As the charged particle moves, the electric field and magnetic field keep changing, which causes the wave to move.

Explanation:

<em> I just answered the question and this is the sample response </em>

4 0
3 years ago
Read 2 more answers
A marble column of cross-sectional area 1.6 m^2 supports a mass of 26600 kg. The elastic modulus for marble is 5.0 times 10^10 N
vodka [1.7K]

Answer:

Δ L = 2.57 x 10⁻⁵ m

Explanation:

given,

cross sectional area = 1.6 m²

Mass of column = 26600 Kg

Elastic modulus, E = 5 x 10¹⁰ N/m²

height = 7.9 m

Weight of the column = 26600 x 9.8

                                    = 260680 N

we know,

Young's modulus=\dfrac{stress}{strain}

stress = \dfrac{P}{A}

           = \dfrac{260680}{1.6}

           = 162925

strain = \dfrac{\Delta L}{L}

now,

Y = \dfrac{stress}{strain}

\Delta L = \dfrac{162925}{Y}\times L

\Delta L = \dfrac{162925}{5 \times 10^10}\times 7.9

   Δ L = 2.57 x 10⁻⁵ m

The column is shortened by Δ L = 2.57 x 10⁻⁵ m

3 0
3 years ago
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