Let A = 0.0009, it is equivalent to A = 9^-4 = (9^-2)^2
so sqrt A =sqrt (9^-2)^2 = (9^-2)
<span>he real square roots of 0.0009 is 0.09</span>
104 and 105 are consecutive numbers that add up to 209. Maybe this answers your question? Let me know otherwise.
A.4x=16+5
4x=21
x=21/4
x=5.25
b.I am not sure about the question too much as solution for the question above
35+3x-11=2335+3x-11
have no solution but,
for 2335+3x-11=23
3x=23+11-2335
=-2301
x =-2301/3
=-767.00
420-x=76 try that equation if not you might want a math tutor.
