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3 years ago

Anyoneknodacorrectanswer

Mathematics

1 answer:

creativ13 [48]3 years ago

3 0

Answer:IknowdacorrectansweritisA

Step-by-step explanation:

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Which product of prime polynomials is equivalent to 4x5 – 6x4 + 4x3 – 6x2?

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Answer:

4 x^5 - 6 x^4 + 4 x³ - 6 x² =

Answer: 1 ) 2 x² ( x² - 1 ) ( 2 x - 3 )

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3 years ago

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Sergeu [11.5K]

The answer is letter B

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3 years ago

Find the domain of the function expressed by the formula:

Simora [160]

Answer:

a. Domain - x= all real numbers

b. Domain - x= all real numbers except 0

c. Domain - x= all real numbers

d. Domain - x= All real numbers

Step-by-step explanation:

The domain of a function is all the possible x values. It is easy to solve for domain by graphing the function.

a graph - blue

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3 years ago

DATA MANAGEMENT GRADE 12! HELP

Mashcka [7]

There are winnings of $50 ( 60% ), $100 ( 20% ) and $1,000 ( 2% ).
$50 * 0.6 = $30
$100 * 0.2 = $20
$1,000 * 0.02 = $20
$30 + $20 + $20 = $70
Answer: The expected payout per fan is $70.

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3 years ago

PLs answer fast i need this questions answer

Mashutka [201]

Answer:

$x=6$

Step-by-step explanation:

Given equation:

$x-\left(2x-\dfrac{3x-4}{7}\right)=\dfrac{4x-27}{3}-3$

Expand the left side:

$\implies x-2x+\dfrac{3x-4}{7}=\dfrac{4x-27}{3}-3$

Let all terms on the left side have the same denominator of 7:

$\implies \dfrac{7x}{7}-\dfrac{14x}{7}+\dfrac{3x-4}{7}=\dfrac{4x-27}{3}-3$

Join the terms on the left side:

$\implies \dfrac{7x-14x+3x-4}{7}=\dfrac{4x-27}{3}-3$

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-27}{3}-3$

Let all the terms on the right side have the same denominator of 3:

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-27}{3}-\dfrac{9}{3}$

Join the terms on the right side:

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-27-9}{3}$

$\implies \dfrac{-4x-4}{7}=\dfrac{4x-36}{3}$

Cross multiply:

$\implies 3(-4x-4)=7(4x-36)$

Expand:

$\implies -12x-12=28x-252$

Add 12x to both sides:

$\implies -12=40x-252$

Add 252 to both sides:

$\implies 240=40x$

Divide both sides by 40:

$\implies 6=x$

$\implies x=6$

6 0

1 year ago