What do I put at the end of a brochure

What is a joint production process? Describe a special decision that commonly arises in the context of a joint production proces

Tanya [424]

Answer:

Quy trình sản xuất nói chung là quá trình con người tác động vào tài nguyên thiên nhiên để biến chúng thành các sản phẩm có ích cho xã hội.

Explanation:

8 0

2 years ago

In need of extra cash, Troy and Lily decide to withdraw $2 comma 100 from their traditional IRA. They are both 40 years old. T

krek1111 [17]

Answer:

Calculate the tax consequence of withdrawal from retirement account.

T and L are 40 years old and decide to withdraw $2,100 from their IRA. They lie in a 35% marginal tax bracket.

Analysis

They are withdrawing some amount from their retirement fund. They have to pay the tax and penalty for early withdrawals from the retirement fund. The withdrawal amount is $2,100 so they have to pay tax on it. The tax rate will be 35% which is their marginal tax bracket.

Calculation of tax consequences if withdrawal amount is $2,100:

Ordinary income tax amount calculates by multiplying the withdrawal amount with the ordinary tax rate.

= $2100 × 35%

= $735

The withdrawal amount attracts the 10% penalty. So, the penalty amount is calculated as follows: Penalty on withdrawn funds calculates by multiplying the withdrawn funds with the percentage of penalty.

= $2100 × 10%

= $210

(NOTE: - T and L have to pay ordinary income tax along with the penalty on their withdrawal because they are withdrawing funds from their IRA before age 59.5.)

Total expenses include the tax amount and penalty charge on withdrawal amount. So, it is calculated as follows:

Total expenses =$735 + $210

Total expenses = $945

Conclusion

Therefore, T and L would incur a tax of $945 on their withdrawal. This $945 is the sum of income tax amount and penalty on withdrawal balance.

8 0

2 years ago

A property title search firm is contemplating using online software to increase the productivity of the researcher performing th

Stella [2.4K]

Answer:

PRESENT= $5.21

COMPANY – A = $6.72

COMPANY – B= $6.64

Explanation:

Calculation for the higher productivity in terms of revenue per dollar of input

PRESENT

Average time =59 minutes

Cost=59 minutes x$1.30 per minute

Cost = $76.7

Productivity (per $input)=$400/$76.7

Productivity (per $input)= $5.21

COMPANY – A

Average time= (59 minutes-16 minutes)

Average time=43 minutes

Cost= 43 minutes x $1.30 per minute + $3.60

Cost=$55. 9+$3.60

= $59.50

Productivity (per $input)=$400/$59.50

Productivity (per $input) = $6.72

COMPANY – B

Average time= (59 minutes - 17 minutes)

Average time=42 minutes

Cost= 42 minutes x $1.30 per minute + $5.60

Cost=$54. 6+$5.60

= $60.20

Productivity (per $input)=$400/$60.20

Productivity (per $input) = $6.64

Summary

PRESENT:Productivity (per $input)= $5.21

COMPANY – A:Productivity (per $input) = $6.72

COMPANY – B:Productivity (per $input) = $6.64

Therefore COMPANY – A with the amount of $6.72 would have the higher productivity in terms of revenue per dollar of input because it has the highest amount.

4 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi

Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

$\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}$

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

$1000000\sqrt{9+x^{2}$

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)$

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000$

$f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}} = 500000\\\frac{2x}{\sqrt{9+x^2}} = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\$

And we plug square root of 3 in the original cost function ad we get

$f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\$