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il63 [147K]
3 years ago
15

In what century were negative integers finally accepted?

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0

Answer:Sixteenth century

Step-by-step explanation:

In sixteenth century the negative numbers got acceptable.

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Divide. 1 4/9 ÷ 2/3 pls help
kaheart [24]

1 4/9 ÷ 2/3 = 13/9 x 3/2 = 13/6

ok done. Thank to me :>

6 0
3 years ago
Could someone help me out for number 5 please?
kifflom [539]

Answer:

she didnt multiply 5 times 12

7 0
4 years ago
I am really stuck on this problem​
oksian1 [2.3K]

Answer:

1. ∠1 = 60

2. ∠2 = 40

3. ∠3 = 80

4. ∠4 = 80

5. ∠5 = 60

6. ∠6 = 120

7. ∠7 = 100

8. ∠8 = 60

9. ∠9 = 120

10. ∠10 = 100

Step-by-step explanation:

8 0
3 years ago
Plz help!!!! Geometry
never [62]

The little lines inside the two angles mean they are the same.

The 3 inside angles of a triangle equal 180 degrees.

One angle is 146 , so the other two need to equal 180-146 = 34 total.

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Both angle 1 and angle 2 are 17 degrees each.

8 0
3 years ago
Read 2 more answers
Find f(g(3)) given:<br> *<br> f (x) = 2x2 – 1<br> g(x) = 3x<br> h(x) =<br> j(x) = x - 5
bezimeni [28]

Answer:

161

Step-by-step explanation:

Given the functions

f (x) = 2x^2 – 1

g(x) = 3x

we are to find f(g(3))

First look for the composite function f(g(x))

f(g(x)) = f(3x)

f(3x)  = 2(3x)² - 1

f(3x)  = 2*9x² - 1

f(3x)  = 18x² - 1

f(g(x)) =  18x² - 1

Substitute x  = 3 into the result

f(g(3)) = 18(3)² - 1

f(g(3)) = 18*9- 1

f(g(3)) = 162-1

f(g(3)) = 161

Hence f(g(3)) is 161

5 0
3 years ago
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